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yarga [219]
3 years ago
8

Post-exposure radiation levels are approximately Normally distributed. The levels (in Sv) of a random sample of three trauma vic

tims who were recently exposed are 5.5, 6.2, and 4.8. A 95% confidence interval for the mean based on these data is:
Physics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

0.404

Explanation:

The calculation of confidence interval for the mean is shown below:-

Data provided in the question

Mean = 5.5

The Standard deviation for three values  is 0.7

Since there is 95% of the confidence interval so the critical value is

t_{0.025.5} = 4.303\\

Now

Margin error is

t_{0.025.5} = 4.303\times \frac{s}{\sqrt{n} }

= 4.303\times \frac{0.7}{\sqrt{3} }

= 1.74

Now,

The Standard error is

= \frac{s}{\sqrt{n} }

= \frac{0.7}{\sqrt{3} }

= 0.404

Hence, the confidence interval for the mean based is 0.404

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Help with these questions please , 15 PTS & brainliest
myrzilka [38]

For these two questions, first you need to know that the voltage across each branch of a parallel circuit is the same.

So, for Q5, we can first find out the voltage across R₂ by V=IR.

Voltage across R₂ = 2.5 × 8 = 20V

Since R₂ and R₃ are in parallel circuit, their voltage should be the same. Thus, voltage across R₃ is 20V.

So, by V=IR,

current of R₃ = \frac{20}{4} = 5A

Q6. voltage across R₁ = 2 × 4 = 8V

∴voltage across R₂ = 8V

current of R₂ = \frac{8}{8} = 1A

<h3><u>Alternative method</u></h3>

From these two examples, you can find out that the current of each branch of the parallel circuit is inversely proportional to the resistance of the branch.

ie. for Q5,

\frac{R2}{R3} = \frac{I3}{I2}

\frac{8}{4} = \frac{I3}{2.5}

I₃ = 5A

Q6. \frac{R1}{R2} = \frac{I2}{I1}

\frac{4}{8} = \frac{I2}{2}

I₂ = 1A

6 0
3 years ago
A railroad car moves under a grain elevator at a constant speed of 3.20 m/s. Grain drops into the car at the rate of 240 kg/min.
dedylja [7]

Answer:

F = 768 N                  

Explanation:

It is given that,

Speed of the elevator, v = 3.2 m/s

Grain drops into the car at the rate of 240 kg/min, \dfrac{dm}{dt}=240\ kg/min = 4\ kg/s

We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :

F=\dfrac{dp}{dt}

F=m\dfrac{dv}{dt}+v\dfrac{dm}{dt}

Since, the speed is constant,

F=m\dfrac{dv}{dt}

F=v\dfrac{dm}{dt}

F=3.2\times 240

F = 768 N

So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.

5 0
4 years ago
(a) On the axes below, sketch the graphs of the horizontal and vertical components of the sphere’s velocity as a function of tim
jeka94

Answer:

Two identical spheres are released from a device at time t = 0 from the same ... Sphere A has no initial velocity and falls straight down. ... (b) On the axes below, sketch and label a graph of the horizontal component of the velocity of sphere A and of sphere B as a function of time. ... Which ball has the greater vertical velocity

Explanation:

4 0
3 years ago
We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.2
monitta

Answer:

The number of atoms is N = 4.37*10^{22} \ atoms

Explanation:

From the question we are told that

                 The mass of coin  is m_n = 4.2g

                   Number of atom in one mole = n =6.02*10^{23} \ atoms

                   Molar mass of nickel M = 57.8g

Now the relation to obtain the number of atom in  the  nickel coin is

                        N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel }  * No\ of\atoms \ in \ \ one\  mole\ of\ nickel

                           = \frac{4.2}{57.8}* 6.02*10^{23}

                           =4.37 *10^{22} atoms

                 

     

8 0
3 years ago
A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,
wlad13 [49]
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
\Delta U + \Delta K=0
which means
\Delta K = - \Delta U
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (\Delta V=-1000 V):
\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV
Therefore, the kinetic energy gained by the proton is
\Delta K = -(-1000 eV)=1000 eV
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
4 0
3 years ago
Read 2 more answers
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