Answer:
Explanation:
First I sketched the compression of the gas with the help of the given pressure change process relation. That is your pressure change due to change in volume.
To find the area underneath the curve (the same as saying to find the work done) you should integrate the given relation for pressure change:
2.31 ft/psig
1.98 psig would equalize feet of head 4’7”
4.583/2.31 = 1.98. .583 is 7”/12”
So round off to 2.0 psig to get steady stream of bubbles
Answer:
see explaination for all the answers and full working.
Explanation:
deflection=8P*DN/Gd^4
G(for steel)=70Gpa=70*10^9N/m^2=70KN/mm^2
for outer spring,
deflection=8*3*50^3*5/(70*9^4)=32.66mm
for inner spring
deflection=8*3*30^3*10/(70*5^4)=148.11mm
max stress=k*8*P*C/(3.14*d^2)
for outer spring
c=50/9=5.55
k=(4c-1/4c-4)+.615/c=1.2768
max stress=1.2768*8*3*5.55/(3.14*9^2=.66KN.mm^2
for inner spring
c=6
k=1.2525
max stress=2.29KN/mm^2
Answer:
i) 3750 veh/hr/ln
ii) 100 veh/mi/In
iii) 37.5 mph
Explanation:
number of lanes = 3
sf for both directions = 75 mph ( free mean speed )
Dj for both directions = 200 veh/mi/In
<u>Calculate the value of S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)</u>
For either direction we will consider the total volume = 3 lanes
value of Dj = 3 lanes * 200 = 600 veh/mi/
i) value of SO
= ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr = 3750 veh/hr/lane
ii) Value of DO
DO = Dj / 2 = 200 /2 = 100 veh/mi/In
iii) Value of Vm
= sf /2 = 75 / 2 = 37.5 mph
