Answer:
Mah dood! I gatchu! Dae ansa iz A! I gatchu fam! I gatchu Brochacho!
Explanation:
it the first one hope this helps
Answer: making sure that they are up to date
Explanation:
Answer:
make contact in a way which fits the industry and is comfortable to you
Explanation:
Terri Duncan was a person that helped people going for interviews by offering them professional advice on how to compose and conduct themselves during an interview.
Terri Duncan also helps people going for interviews but providing them with the aid they need concerning what to say during an interview.
Terri Duncan recommends following up after an interview by making contact in a way which fits the industry and is also comfortable to you.
Answer:
a) 2.18 m/s^2
b) 9.83 m/s
Explanation:
The flywheel has a moment of inertia
J = m * k^2
Where
J: moment of inertia
k: radius of gyration
In this case:
J = 144 * 0.45^2 = 29.2 kg*m^2
The block is attached through a wire that is wrapped around the wheel. The weight of the block causes a torque.
T = p * r
r is the radius of the wheel.
T = m1 * g * r
T = 18 * 9.81 * 0.6 = 106 N*m
The torque will cause an acceleration on the flywheel:
T = J * γ
γ = T/J
γ = 106/29.2 = 3.63 rad/s^2
SInce the block is attached to the wheel the acceleration of the block is the same as the tangential acceleration at the eddge of the wheel:
at = γ * r
at = 3.63 * 0.6 = 2.81 m/s^2
Now that we know the acceleration of the block we can forget about the flywheel.
The equation for uniformly accelerated movement is:
X(t) = X0 + V0*t + 1/2*a*t^2
We can set a frame of reference that has X0 = 0, V0 = 0 and the X axis points in the direction the block will move. Then:
X(t) = 1/2*a*t^2
Rearranging
t^2 = 2*X(t)/a


It will reach the 1.8 m in 3.6 s.
Now we use the equation for speed under constant acceleration:
V(t) = V0 + a*t
V(3.6) = 2.81 * 3.6 = 9.83 m/s