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snow_tiger [21]
4 years ago
15

99 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!
Which of the following questions are appropriate to ask an engineer in an interview?

1. Can you tell me something about yourself?

2. What are your weaknesses?

3. If you would describe yourself in one word?

4. Why did you leave your last position?

5. How do you deal with pressure or stressful situations?
Engineering
2 answers:
Akimi4 [234]4 years ago
8 0

Answer:

5

Explanation:

qwelly [4]4 years ago
7 0

Answer:

1. Can you tell me something about yourself?

2. What are you weaknesses?

3. If you would describe yourself in one word?

Explanation: Those questions above 1, 2, and 3 are not harmful to ask your client. Bit the last two 4 and 5 are very harmful, because you don't need to be all up in they business and you don't want to put a lot of pressure on your client.

Hope this helps☝️☝☝

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(a) If 5 x 10^17 phosphorus atoms per cm3 are add to silicon as a substitutional impurity, determine the percentage of silicon a
Y_Kistochka [10]

Answer:

The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice = 0.001 %

The percentage of silicon atoms per unit volume that are displaced in the single crystal lattice with boron atoms = 0.4 ×10^{-5} %

Explanation:

No. of phosphorus atoms = 5 × 10^{17} \ cm^{-3}

The volume occupied by a single Si atom

V_{si} = \frac{a^{3} }{8}

V_{si} = \frac{5.43^{3}(10^{-8} )^{3}  }{8}

V_{si} = 2 × 10^{-23} \frac{cm^{3} }{atom}

n_{si} = \frac{1}{V_{si} }

n_{si} = 5 × 10^{22} \frac{atoms}{cm^{3} }

PCT = \frac{N_p}{N_{si}}   100

Put the values in above equation we get

PCT = \frac{5 (10^{17} )}{5 (10^{22}) } 100

PCT = 10^{-3} = 0.001 %

These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.

(b).

No. of boron atoms = 2 × 10^{15} \ cm^{-3}

The volume occupied by a single Si atom

V_{si} = \frac{a^{3} }{8}

V_{si} = \frac{5.43^{3}(10^{-8} )^{3}  }{8}

V_{si} = 2 × 10^{-23} \frac{cm^{3} }{atom}

n_{si} = \frac{1}{V_{si} }

n_{si} = 5 × 10^{22} \frac{atoms}{cm^{3} }

PCT = \frac{N_p}{N_{si}}   100

Put the values in above equation we get

PCT = \frac{2 (10^{15} )}{5 (10^{22}) } 100

PCT = 0.4 ×10^{-5} %

These are the percentage of silicon atoms per unit volume that are displaced in the single crystal lattice.

7 0
3 years ago
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