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Nina [5.8K]
3 years ago
6

153 is 0.9% of what number tell which equivalent ratios are used to find a solution

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

17,000

Step-by-step explanation:

Klio2033 [76]3 years ago
4 0

Answer: Answer: 153 is 0.9% of 17000.

(brainly please)

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HEy, CAn YOu HElp ? :) Plssss (picture below) solve for #5
alexira [117]

Answer: a=60°, b=25°, c=95°,d=60°, e=25°, f=95°, g=60, h=35°

Step-by-step explanation:

a=60°, Because the angle opposite to it is 60°

b=25°, Because if you take 180°-155°, you get 25°

c=95°, Because if you add angles a and b, you get 85°, then you do 180°-85°=95°

d=60°, Because the angle opposite to it does

f=95°, Because angle c, which is opposite to it equals 95°

g=60°, Because if you add angles e and f, you get 85°, then you take 180°-85=95°

h=35°, Because if you add angles c and d, which is 155°, you take 180°-155=35°

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Answer:

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Step-by-step explanation:

8 0
3 years ago
The length of a parasite in experiment A is 2.5 × 10–3 inch. The length of a parasite in experiment B is 1.25 × 10–4 inch. How m
torisob [31]

We have been given that :-

The length of a parasite in experiment A is 2.5 \times 10^{-3}

The length of a parasite in experiment B is 1.25 \times 10^{-4}

Let us write the the  length of the parasite in experiment A in the exponent of -3.

1.25 \times 10^{-4}= 0.125 \times 10^{-3}

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.

The difference in the length is given by

2.5 \times 10^{-3} -0.125 \times 10^{-4}

=2.375 \times 10^{-3}

Therefore, the length of the parasite in experiment A is =2.375 \times 10^{-3} inches  greater than the length of the parasite in experiment B.

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3 years ago
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never [62]

Answer:

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Step-by-step explanation:

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15pts<br> f(x)=(x+6)/2<br> g(x)=2x - 6<br> Show your work to evaluate g(f(x)).
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Answer:

g(f(x)) = -x - 18

Step-by-step explanation:

2x - 6( (x + 6) / (2) )

2x - 3( x + 6)

2x - 3x - 18

-x - 18

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