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Vsevolod [243]
3 years ago
10

The units for potential energy PE are?

Physics
2 answers:
rewona [7]3 years ago
4 0
The units for potential energy PE are Joules (J)

S_A_V [24]3 years ago
4 0

Answer:

the unit for PE is joule's

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How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 45 j of work?
bija089 [108]

Here is your answer

5 coulomb

REASON :

We know that

Potential difference, V= W/q

where, W is work done

and, q is magnitude of charge

Given,

V= 9.0 v and W= 45 J

So,

using above relation, we get

9= 45/q

q= 45/9

q= 5 coulomb

HOPE IT IS USEFUL

6 0
3 years ago
Light is an example of a mechanical wave in nature? true or false
Zina [86]

Answer:

The answer is False.

Explanation:

The Light is a form of energy ( known as luminous energy ) that can be perceived by the human eye, therefore it allows us to see what surrounds us. Light is an electromagnetic radiation that spreads in the form of spherical waves in any space, consequently, it is not a mechanical wave.

5 0
4 years ago
Read 2 more answers
1 Find the acceleration of an object if there is a force of 20 newtons in one direction and 10 newtons in the opposite direction
Zielflug [23.3K]

Answer:

5m/s/s

Explanation:

10N bc you subtract 10N from 20N and you get 10

a=f/m

F=10N

m=2kg

10/2=5

7 0
3 years ago
Different velocity-time graph lines are shown, displaying the behavior of multiple race carts along a linear track.
Studentka2010 [4]

B) Moving with zero acceleration.

Explanation:

Acceleration is defined as the rate of change of the velocity per unit time:

a=\frac{\Delta v}{\Delta t}

In a velocity-time graph, this ratio corresponds to the slope of the curve. In fact:

\Delta v (change in velocity) corresponds to the increase in the y-axis

\Delta t (change in time) corresponds to the increase in the x-axis

So, acceleration corresponds to the slope of the curve in a velocity-time graph. For cart C, the slope is zero, therefore the acceleration is also zero.

8 0
3 years ago
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Ship A is located 4.2 km north and 2.7 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a vel
kotykmax [81]

Answer:

(a) The x-component of velocity is 31.55 km/h

(b) The y-component of velocity is 44.92 km/hr

Solution:

As per the solution:

The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.

Velocity of ship A, \vec{u_{A}} = 22 km/h towards South = - 22\hat{j}

Velocity of ship B, \vec{u_{B}} = 39 km/h Towards North east at an angle of 36^{\circ} = \vec{u_{B}} = 39sin36^{\circ} \hat{j}

Now, the velocity of ship A relative to ship B:

\vec{u_{AB}} = \vec{u_{A}} - \vec{u_{B}}

\vec{u_{A}} = - 22\hat{j}

\vec{u_{B}} = 39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}

Now,

\vec{u_{AB}} = - 22\hat{j} +39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}

\vec{u_{AB}} = 31.55\hat{i} - 44.92\hat{j}

4 0
3 years ago
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