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3 years ago

A pool and stops at the

Physics

1 answer:

Bas_tet [7]3 years ago

8 0

In Linear motion the swimmer swims

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aleksley [76]

Where is the question

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3 years ago

In a particular case of an object in front of a spherical mirror with a focal length of +12.0 cm, the magnification is +4.00.(a)

salantis [7]

Answer:

9 cm

-36 cm

Explanation:

u = Object distance

v = Image distance

f = Focal length = 12

m = Magnification = 4

$m=-\frac{v}{u}\\\Rightarrow 4=-\frac{v}{u}\\\Rightarrow v=-4u$

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{12}=\frac{1}{u}+\frac{1}{-4u}\\\Rightarrow \frac{1}{12}=\frac{3}{4u}\\\Rightarrow u=9\ cm$

Object distance is 9 cm

$v=-4\times 9=-36\ cm$

Image distance is -36 cm (other side of object)

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3 years ago

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Nookie1986 [14]

Answer:

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3 years ago

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3 years ago

Which description does the phrase "mechanical advantage" most closely relate to?

yKpoI14uk [10]

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3 years ago