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Andre45 [30]
1 year ago
8

A line with a slopeof 8/7 passes through the point (7,8). what is its equation in slope-intercept form?

Mathematics
1 answer:
saw5 [17]1 year ago
6 0

8x - 7y = 0 is the equation in slope-intercept form of the line with a slope of 8/7 passes through the point (7,8). This can be obtained using the formula of equation for the Slope Intercept Form.  

<h3>What is its equation in slope-intercept form?</h3>

The formula of equation for the Slope Intercept Form is given below,

y = mx + b,

where m is the slope of the line, b is the y intercept where the line crosses the y-axis at (0, b).

Here in the question it is given that,

  • The slope of the line is 8/7
  • The line passes through the point (7,8)

We have to find the equation in slope-intercept form.

By using formula of equation for the Slope Intercept Form we get,

y = mx + b,

here,

⇒ from the point (7, 8), x = 7 and y = 8

⇒ slope, m = 8/7

To find y intercept we use the slope-intercept form equation,

y = mx + b

8 = (8/7)7 + b

8 = 8 + b

⇒ b = 0

Thus the equation in slope-intercept form will be,

y = mx + b

⇒ y = (8/7)x + 0

⇒ 7y = 8x

⇒ 8x - 7y = 0

Hence 8x - 7y = 0 is the equation in slope-intercept form of the line with a slope of 8/7 passes through the point (7,8).

Learn more about slope-intercept form here:

brainly.com/question/9682526

#SPJ4

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Answer:

  • <u>5</u><u> </u>is the value which makes the equation true .

Step-by-step explanation:

In this question we have provided an equation that is <u>9</u><u> </u><u>(</u><u> </u><u>3x</u><u> </u><u>-</u><u> </u><u>1</u><u>6</u><u> </u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>5</u><u> </u><u>=</u><u> </u><u>6</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u>4</u><u> </u>. And we are asked to <u>write </u><u>the </u><u>steps </u><u>to </u><u>solve </u><u>the </u><u>equation </u><u>with </u><u>explanation </u> and <u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>X </u><u>.</u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

\longmapsto \quad \: 9(3x - 16) + 15 = 6x - 24

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis on left side using distributive property which means multiplying 9 with 3x as well as -16 :

\longmapsto \quad \:27x -  \bold{144 }+  \bold{15 }= 6x - 24

<u>Step </u><u>2</u><u> </u><u>:</u> Solving like terms on left side that are -144 and 15 :

\longmapsto \quad \:27x -129 = 6x - 24

<u>Step </u><u>3 </u><u>:</u> Adding 129 on both sides :

\longmapsto \quad \:27x - \cancel{129} -  \cancel{129} = 6x \bold{ - 24 } +  \bold{129}

Now on cancelling -129 with 129 on left side and solving the terms that are -24 and 129 on right side , We get :

\longmapsto \quad \:27x = 6x + 105

<u>Step </u><u>4</u><u> </u><u>:</u> Subtracting with 6x on both sides :

\longmapsto \quad \: \bold{27x} -  \bold{6x} =  \cancel{6x} +105 - \cancel{ 6x}

On calculating further, We get :

\longmapsto \quad \:21x =  105

<u>Step </u><u>5</u><u> </u><u>:</u> Now we are Dividing with 21 on both sides so that we can isolate the variable that is x :

\longmapsto \quad \: \dfrac{ \cancel{21}x}{ \cancel{21}}  = \dfrac{105}{ 21}

Now , by cancelling 21 with 21 on left side , We get :

\longmapsto \quad \:x =  \cancel{\dfrac{105}{21}}

<u>Step </u><u>6</u><u> </u><u>:</u> Now our final step is to simplify the value of x that is 105/21 . We know that 21 × 5 is equal to 105 . So :

\longmapsto \quad \:    \purple{\underline{\boxed{\frak{ x =  5 }}}}

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Now we are verifying our answer by substituting value of x in the given equation . So ,

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  • 9 [ 3 ( 5 ) - 16 ] + 15 = 6 ( 5 ) - 24

  • 9 ( 15 - 16 ) + 15 = 30 - 24

  • 9 ( -1 ) + 15 = 6

  • -9 + 15 = 6

  • 6 = 6

  • L.H.S = R.H.S

  • Hence , Verified .

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