There’s tutors for math i just asked a tutor for help lol
P3(4) = p12 them p12 * p8 = P160 (false)
<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260
Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320
I hope this helps! :)
According to the priority level of their service level packages and problems,the technician visit the customers visits in the following order.
1) Platinum service level
2) Gold Service level
3) <span>Silver service level
4) Bronze service level
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