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Dvinal [7]
3 years ago
9

The difference between two numbers is 9. The first number plus twice the other number is 27.Find the two numbers.

Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0
The numbers are 3 and 12. 12 and 3 have a difference of 9 and 3+12+12=27.
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Answer:

0.75

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What is the range of the function: {(1, 3); (3, 5); (5, 7); (7, 9)}?                                     A. {1, 3, 5, 7}        
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\{(1;\ \underline{3});\ (3;\ \underline{5});\ (5;\ \underline{7});\ (7;\ \underline{9})\}\\\\Range\ of\ this\ function:\{3;\ 5;\ 7;\ 9\}\\\\Domain\ of\ this\ function:\{1;\ 3;\ 5;\ 7\}
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3 years ago
ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
Alex Ar [27]

NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
  • square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
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Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

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5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

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I hope this helps you

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