Use for loop and question inside it
Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / ~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer:
It allows for Non-linear editing
Answer:
Client server system, packets in the network and the discussion regarding two approaches have been done. See the attached pictures.
Explanation:
See attached pictures for explanation.
Answer:
having a capital and lower case letters and a special characters and numbers.
Explanation:
it should be hard but easy enough to remember and no one will know