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andreyandreev [35.5K]
3 years ago
11

What is the value of x​

Mathematics
1 answer:
Len [333]3 years ago
3 0

Answer:

X=70

Step-by-step explanation:

Interior angles of parallel line sum up to be 180° so:

45+(2x-5)=180

45+2x=185

2x=140

x=70

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LMN≅PQR
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<span>LMN≅PQR means that point L is equal to P, point M is equal to Q, and point N is equal to R. All lines are the same.

Point Q has an angle of 72, which means that point M also has an angle of 72.

Now you have two angles to find x. All interior angles of a triangle add up to 180, so you can set up the following equation to find x:

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Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call
Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is M = n\mu and the standard deviation is s = \sigma\sqrt{n}

Calls to a customer service center last on average 2.8 minutes.

This means that \mu = 2.8

75 calls each day.

This means that n = 75

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

M = n\mu = 75*2.8 = 210

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

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