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djyliett [7]
1 year ago
12

Where do you find a vertical shift in the exponential parent function?

Mathematics
1 answer:
Montano1993 [528]1 year ago
4 0

For the given expressions we will have:

y = exp(x - 4)   →we have a shift of 4 units to the right.

y = exp (x +9)  → we have a shift of 9 units to the left.

y = exp(x) + 7 → we have a shift of 7 units up.

y = exp(x) - 6  → we have a shift of 6 units down.

<h3>How to work with vertical and horizontal shifts?</h3>

Remember that the shifts work as follows.

For a function f(x), we define a vertical shift of N units as:

g(x) = f(x) + N

  • If N > 0, the shift is upwards.
  • If N < 0, the shift is downwards.

For a function f(x), we define a horizontal shift of N units as:

g(x) = f(x + N)

  • If N > 0, the shift is to the left.
  • If N < 0, the shift is to the right.

Then, if we have:

exp(x - 4) we have a shift of 4 units to the right.

exp (x +9) we have a shift of 9 units to the left.

exp(x) + 7 we have a shift of 7 units up.

exp(x) - 6  we have a shift of 6 units down.

Learn more about translations

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Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0
3 years ago
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Find the perimeter. Simplify your answer.<br> 4c+9<br> 70-5<br> 5c+2<br> 5c-3
pickupchik [31]

Answer:

Step-by-step explanation:

Perimeter = 4c + 9 + 7c - 5 + 5c + 2 + 5c - 3

                = 4c +7c + 5c +5c + 9 - 5 + 2  - 3

                 = 21c + 3

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Round 25,678 to the nearest ten thousand
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Plzzzz I will give you 100 points plzzz
kirza4 [7]

Answer: x < 8/9


Step-by-step explanation:

The equation is 4 * (2x +1) * 4.5 = 50, since the volume is found by multiplying the length, width, and height together, and the =50 part is because our volume can't go above 50 cubic units.


We can simplify 4 * (2x+1) * 4.5 by multiplying 4 and 4.5, which is 18, and then multiplying both 2x and 1 by 18. We get 36x + 18, and we put in the =50, so it is 36x+18=50.

Next, we can subtract 18 from both sides of the equation, giving us 36x = 32.

We then divide the equation by 36 so that we have the x by itself, and we get x = 32/36, which can be simplified to 8/9.


What we're left with is x = 8/9, meaning plugging in 8/9 for the equation would give us 50. However the problem says that the volume must be below 50, so our actual answer is x < 8/9.

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The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation
Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

<u><em>Let X = weights of adult male birds of a certain species</em></u>

So, X ~ Normal(\mu=27.5,\sigma^{2} =1.1^{2})

The z score probability distribution for normal distribution is given by;

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where, \mu = population mean weight = 27.5 grams

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The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

          <u>Z score</u> =  \frac{ X-\mu}{\sigma } } = \frac{ 29.37-27.5}{1.1 } }

                                    =  <u>1.7</u>

                       

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