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telo118 [61]
11 months ago
8

Two waves have the same frequency. What other characteristic must be the same for these waves?.

Physics
1 answer:
madreJ [45]11 months ago
4 0

The wave characteristic that is the same for both waves is wavelength.

  • Two waves with the same frequency will also have the same wavelength, amplitude, speed, and period. When two waves are travelling at the same frequency, it denotes that their duration and amplitude are also the same.
  • When two waves of the same frequency and amplitude interfere constructively, their peaks and troughs align as shown in diagram A above. As a result, the original waves' amplitude is doubled, resulting in a sound wave that is twice as loud.

Thus, Equal frequencies are shared by two waves moving through the same region in the same direction.

To know more about wave

brainly.com/question/17076990

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the horizontal velocity while it was falling is 22.1 m/s.

Explanation:

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The horizontal velocity is calculated as;

v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s

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imagine that 501 people are present in a movie theater of volume 8.00 x10^3 that is sealed shut so no air can escape. Each perso
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Answer:

The temperature of air will increase by \Delta T=41044.967\ K

Explanation:

Given:

  • no. of person in a theater, n=501
  • volume of air in the theater, V=8\times 10^3\ m^3
  • rate of heat given off by each person, P=110\ J.s^{-1}
  • duration of movie, t=2\ hr=7200\ s
  • initial pressure in the theater, p_i=1.01\times 10^5\ Pa
  • initial temperature in the theater, T_i=20+273=293\ K
  • specific heat capacity of air at the given conditions, c=1.0061\ J.kg^{-1}.K^{-1}

<u>The total quantity of heat released by the total people in the theater during the movie:</u>

Q=n.P.t

Q=501\times 110\times 7200

Q=396792000\ J

<u>Form the relation of heat capacity:</u>

Q=m.c.\Delta T

∵p_i.V=m.R.T

Q=(\frac{p_i.V}{R.T}) \times c\times (T_f-T_i)

396792000=(\frac{1.01\times 10^5\times 8\times 10^3}{287\times 293}) \times 1.0061\times (T_f-293)

T_f=41337.967\ K

Change in temperature of air:

\Delta T=41044.967\ K

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