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3 years ago

Why do physicists use models?

Physics

2 answers:

svetoff [14.1K]3 years ago

6 0

To see if the project is actually going to work. Also called prototypes

astra-53 [7]3 years ago

3 0

Answer:

Sometimes the phenomena are too complex to be actually explained in totality. In these cases, in order to explain the phenomena, the scientist needs to "simplify" the phenomena.

They can do it by idealizing some things, supposing that some things do not change, and things like that. This is called a "model" of the phenomena. This model helps to explain and work (to a certain extent) with this phenomena, because makes it a lot simpler to work with (experimental wise and mathematical wise)

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True/false: you should begin viewing a specimen with the 10x objective lens.

Nezavi [6.7K]

You should begin viewing a specimen with the 10X objective lens that is false.

An optical device known as a lens uses refraction to focus or disperse a light beam. A compound lens is made up of multiple simple lenses (elements), typically aligned along a common axis, as opposed to a simple lens, which is one solid piece of transparent material. Glass or plastic are used to make lenses, which are then polished or molded into the required shape. In contrast to a prism, which just refracts light without focusing it, a lens can focus light to create an image. In addition to focusing visible light, lenses can also be used to disperse various types of waves and radiation, such as explosive, microwave, electron, and acoustic waves.

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8 0

2 years ago

A circular coil has a 8.79 cm radius and consists of 42.0 closely wound turns of wire. An externally produced magnetic field of

OverLord2011 [107]

Answer: The magnetic flux is 3.4 × 10^-3 Wb

Explanation: Please see the attachments below

8 0

3 years ago

Male Rana catesbeiana bullfrogs are known for their loud mating call. The call is emitted not by the frog's mouth but by its ear

Sidana [21]

Answer:

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

The sound level is 84 dB

The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

8 0

3 years ago

In the figure, a weightlifter's barbell consists of two identical small but dense spherical weights, each of mass 50 kg. These w

kondaur [170]

The moment of inertia is $24.8 kg m^2$

Explanation:

The total moment of inertia of the system is the sum of the moment of inertia of the rod + the moment of inertia of the two balls.

The moment of inertia of the rod about its centre is given by

$I_r = \frac{1}{12}ML^2$

where

M = 24 kg is the mass of the rod

L = 0.96 m is the length of the rod

Substituting,

$I_r = \frac{1}{12}(24)(0.96)^2=1.84 kg m^2$

The moment of inertia of one ball is given by

$I_b = mr^2$

where

m = 50 kg is the mass of the ball

$r=\frac{L}{2}=\frac{0.96}{2}=0.48 m$ is the distance of each ball from the axis of rotation

So we have

$I_b = (50)(0.48)^2=11.5 kg m^2$

Therefore, the total moment of inertia of the system is

$I=I_r + 2I_b = 1.84+ 2(11.5)=24.8 kg m^2$

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6 0

3 years ago

The absolute pressure in water at a depth of 5m is read to be 145 kPa. Determine (a) the local atmospheric pressure, and (b) the

irga5000 [103]

Answer:

a) 95950 pascals

b) 137642.5 pascals

Explanation:

The absolute pressure (Pabs) on a fluid is:

$P_{abs}=P_{gauge}+P_{atm}$ (1)

With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:

$P_{gauge}=\rho gh$ (2)

with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:

$P_{atm}=P_{abs}-P_{gauge}=P_{abs}-\rho_{water} gh$

$P_{atm}=(145000Pa)-(1000\frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})(5m)$

$P_{atm}=95950Pa$

b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

$S.G=\frac{\rho_{fluid}}{\rho_{water}}$

$\rho_{liquid}=S.G*\rho_{water}$

$\rho_{liquid}=(0.85)*(1000\frac{kg}{m^{3}})=850\frac{kg}{m^{3}}$

so:

$P_{abs}=\rho_{liquid} gh+P_{atm}=(850\frac{kg}{m^{3}})(9.81\frac{m}{s})(5m)+95950Pa$

$P_{abs}=137642.5 Pa$

3 0

3 years ago