Basic properties that will be used:

![x^{1/n}=\sqrt[n]x](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%3D%5Csqrt%5Bn%5Dx)

All of these expression can be written to match on or more of the patterns above.
![19.\quad\log_5\sqrt[4]{25}=\log_5(5^2)^{1/4}=\dfrac14\log_55^2=\dfrac12\log_55=\dfrac12](https://tex.z-dn.net/?f=19.%5Cquad%5Clog_5%5Csqrt%5B4%5D%7B25%7D%3D%5Clog_5%285%5E2%29%5E%7B1%2F4%7D%3D%5Cdfrac14%5Clog_55%5E2%3D%5Cdfrac12%5Clog_55%3D%5Cdfrac12)



![27.\quad\log_3\sqrt[6]{243}=\log_3(3^5)^{1/6}=\dfrac16\log_33^5=\dfrac56\log_33=\dfrac56](https://tex.z-dn.net/?f=27.%5Cquad%5Clog_3%5Csqrt%5B6%5D%7B243%7D%3D%5Clog_3%283%5E5%29%5E%7B1%2F6%7D%3D%5Cdfrac16%5Clog_33%5E5%3D%5Cdfrac56%5Clog_33%3D%5Cdfrac56)
By definition, if
is the least upper bound of the set
, it means two thing:
In other words, the least upper bound of a set is greater than or equal to every single element of the set, but it is "close enough" to the elements of the set, because you guaranteed to find elements in the set between
and 
For example, pick
. Obvisouly, the least upper bound is
. In fact, every number in
is smaller than 10, but as soon as you take away something from 10, say 0.01, you get 9.99, and there are elements in
greater than 9.99, say 9.9999.
So, the claim is basically proven by definition: if
, let
. By definition, there exists
.
Answer:
width: 5.5 yd; length: 8 yd
Step-by-step explanation:
Let w represent the width of the rectangle in yards. Then 2w-3 is the length and the area is the product of length and width:
w(2w-3) = 44
2w^2 -3w -44 = 0 . . . . put the equation into standard form
(w+4)(2w -11) = 0 . . . . . factor the equation
w = -4 or 11/2 . . . . . . . . the negative solution is extraneous
Then the length is 2·(11/2) -3 = 8.
The width of the rectangle is 5.5 yards; the length is 8 yards.
One solution. 220/-10x = -22