Pretend the cost of the hotel is called "x" and the amusement park is "y"
make the equations.
450=3x+2y and 700=5x+3y
since you're solving for amusement park, you basically just solve for y
multiply the first equation by 5 and the second equation by 3.
2250=15x+10y and 2100=15x+9y
these are a system of equations so subtract one from the other to cancel the x values away.
150=y so the answer is that a day trip to the amusement park costs $150
Given:
μ = 500 days, the population mean
σ = 60 days, the population standard deviation
Therefore
μ + σ = 560
μ - σ = 440
μ + 2σ = 620
μ - 2σ = 380
μ + 3σ = 680
μ - 3σ = 320
The figure shown below illustrates the normal distribution
About 68% of the total area lies in x = (μ-σ, μ+σ)
About 95% of the total area lies in x = (μ-2σ, μ+2σ)
About 99.7% of the total area lies in x = (μ-3σ, μ+3σ).
Answer:
d=1.4
Step-by-step explanation:
cuz 10-1.4=8.6
<h3>
Answer: 5</h3>
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Work Shown:
x^2 - 5x + 1 = 0
x^2 + 1 - 5x = 0
x^2 + 1 = 5x
(x^2 + 1)/x = 5 .... where x is nonzero
(x^2)/x + (1/x) = 5
x + (1/x) = 5
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An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.
In this case,
p = (5 + sqrt(21))/2
q = (5 - sqrt(21))/2