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zzz [600]
2 years ago
5

Given f(x)=-2x^3 + 3x^2 , find the equation of that tangent line of f at the point where x=2.

Mathematics
1 answer:
trapecia [35]2 years ago
5 0

Step 1: Find f'(x):

f'(x) = -6x^2 + 6x

Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:

f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12

Step 3: Find f(2), so you have a point on y=f(x):

f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4

So, you have the point (2,-4) and the slope of -12.

Step 4: Find the equation of your tangent line:

Using point-slope form you'd have: y + 4 = -12 (x - 2)

That is the equation of the tangent line.

If your teacher is picky and wants slope-intercept, solve that for y to get:

y = -12 x + 20

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Andre types 208 words in 4 minutes. Noah types 342 words in 6 minutes. Who types faster?
Vesna [10]

Answer:

Noah types faster

Step-by-step explanation:

Andre's typing speed per minute - 52 words per minute

\frac{208}{4} = 52

Noah's typing speed per minute - 57 words per minute

\frac{342}{6} = 57

3 0
3 years ago
What is the least common multiple of 3,7,9
KengaRu [80]


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8 0
3 years ago
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for a field trip 12 students rode in cars and the rest filled six buses how many students were in each bus if 342 students were
kolezko [41]

Answer:

55

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4 0
3 years ago
If the area is 2289.06 whats the radius
solniwko [45]
I'm assuming you are referring to the radius of a square

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2289.06/3.14
729

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729^1/2
27

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3 0
3 years ago
What is this question2/3×=1/6​
pickupchik [31]
X is 1/4
2/3 X 1/4 = 1/6 make all have the same bottom number to make it easier

8/12 x 3/12 = 2/12
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3 years ago
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