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3 years ago

1. Cash is

Mathematics

1 answer:

Drupady [299]3 years ago

3 0

Answer:

Untraceable

Step-by-step explanation:

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Z to the power of 5 times z to the power of 6. this equation is exponets.

zheka24 [161]

Answer:

z^11

Step-by-step explanation:

since both terms have "z" and the operation is multiplication, you add the exponents together

6 0

3 years ago

Read 2 more answers

6у – 6 = 4у + 16 A.y=2.2 B. y= -2.2 C. у= 11 D. у= 5

Korvikt [17]

Answer:

C. y=11

Step-by-step explanation:

6y-6=4y+16

6y=4y+22

2y=22

y=11

7 0

2 years ago

Help with question on Complementary and Supplementary Angles

stiks02 [169]

Step-by-step explanation:

Right angle = 90°

(x + 3) + (x - 1) + (x + 1) = 90

3x + 3 = 90, x = 29.

Supplementary angles = Angles that add up to 180°.

x + (x + 104) = 180

2x = 76, x = 38.

8 0

2 years ago

Combine the like terms. 7W-W+3

Bess [88]

The like terms are 7w and -w, so we can collect them to get:

6w+3

Hope this helps!! :)

7 0

3 years ago

The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo

Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = $\frac{0.608}{0.395} = 1.5392$

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0

3 years ago