A sample of lead has the density of 58 g/mL and a mass of 15.2g, what is the volume of the lead?
1 answer:
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Measured volume = 10 ml
mass = 9.925 g
density = 0.9975 g/ml
density =
so actual volume =
= 
= 9.95 mL
Percentage Error =
x 100
=
x 100 = 0.5 % error
mass = 9.925 g
density = 0.9975 g/ml
density =
so actual volume =
Percentage Error =
=
Answer:
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 25.0 L
V₂ = ?
P₁ = 2575 mm Hg
Also, P (atm) = P (mm Hg) / 760
P₁ = 2575 / 760 atm = 3.39 atm
P₂ = 1.35 atm
T₁ = 353 K
T₂ = 253 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 45.0 L</u>
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.