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ivann1987 [24]
3 years ago
6

How many formula units of CaCO3 are present in 4.72 n of calcium carbonate?

Chemistry
1 answer:
arlik [135]3 years ago
4 0

The number of formula units is calculated with the use of Avogadro's constant. That is, on the basis of Avogadro's law:

1 mole = 6.02 × 10²³ formula units

4.72 moles = x formula units

By cross multiplication, we get:

4.72 moles × 6.02 × 10²³ formula units / 1 mole = 2.841 × 10²⁴ formula units.

Thus, the number of formula units of CaCo₃ that are found in 4.72 moles calcium carbonate is 2.841 × 10²⁴.

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Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

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From energy balance equation

Heat lost by alloy = Heat gain by water

m_{a} C_{a}  [T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

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C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

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3 years ago
Pure water at 25°C has a pH of<br> (1) 1 (2) 5 • (3) 7<br> (4) 14
Marysya12 [62]

Answer:

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2 years ago
Which of the following is TRUE? a neutral solution does not contain any H3O+ or OH- a neutral solution contains [H2O] = [H3O+] a
Gnom [1K]

Answer:

Options B and C

Explanation:

Let's take a look at the options and get our answer by way of elimination. The basic definition of a neutral solution is given as;

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7 0
3 years ago
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Fynjy0 [20]

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3 years ago
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The answer to your question is,

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