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ivann1987 [24]
3 years ago
6

How many formula units of CaCO3 are present in 4.72 n of calcium carbonate?

Chemistry
1 answer:
arlik [135]3 years ago
4 0

The number of formula units is calculated with the use of Avogadro's constant. That is, on the basis of Avogadro's law:

1 mole = 6.02 × 10²³ formula units

4.72 moles = x formula units

By cross multiplication, we get:

4.72 moles × 6.02 × 10²³ formula units / 1 mole = 2.841 × 10²⁴ formula units.

Thus, the number of formula units of CaCo₃ that are found in 4.72 moles calcium carbonate is 2.841 × 10²⁴.

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1. Change the following into correct scientific notation.
vlada-n [284]

Answer:

a) 0.03050 = 3.050 × 10-²

b) 0.256 x 10°= 2.56 × 10-¹

c) 25.005 10 =​ 2.500510 × 10¹

Explanation:

Scientific notations is a way of making very large or very small numbers more comprehensive or simplified. It involves the use of power of ten (10^). The numbers are represented to the power of ten. The following format is used:

a x 10^b

where; a is a number or decimal number between 1 and 10 i.e less than 10 but greater than 1

b is the power of ten

To write a number in scientific notation,

- we move the decimal point right or left depending on whether we're trying to reduce or increase the number

- we count the number of times the decimal point was moved. This serves as the b in the format above.

For example,

a) 0.03050 = 3.050 × 10-²

The decimal point was moved rightward twice. This caused the ^-2 power.

b) 0.256 x 10°= 2.56 × 10-¹

The decimal point was moved rightward once. This caused the ^-1 power.

c) 25.005 10 =​ 2.500510 × 10¹

The decimal point was moved leftward once. This caused the ^1 power.

8 0
3 years ago
Guys I need help with 12 and 13 please help!! This packet is due tommorow and I have more 7 pages to do
irinina [24]
12. F - Most of these elements are metals.

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3 0
3 years ago
What is the velocity of a first-order reaction when the reactant concentration is 6 x 10-2M and the rate constant is 8 x 103sec-
tresset_1 [31]

Answer:

D) 4.8 × 10² M/s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

v = k . [A]ⁿ

where,

v: velocity

k: rate constant

[A]: concentration of the reactant A

n: reaction order for A

<em>What is the velocity of a first-order reaction when the reactant concentration is 6 × 10⁻²M and the rate constant is 8 × 10³s⁻¹?</em>

v = k . [A]¹ = 8 x 10³s⁻¹ . 6 x 10⁻²M = 4.8 × 10² M/s

5 0
4 years ago
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3 years ago
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