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12345 [234]
1 year ago
9

pedro has scores of 88,80.83 and 74 after four tests. what score must he make on his fifth test to have an average of 76 or grea

ter?
Mathematics
1 answer:
daser333 [38]1 year ago
3 0

We start to solve this by looking for the formula that let us calculate an average value, this formula would be:

save=\frac{1+s2+s3+s4+s5}{5}

where Save is the average score and s is the score of each exam, Since we know the value of the score Save and 4 of the exams we can replace them in the formula, like this:

And we can solve for s5, which is the score that we need to find, like this:

\begin{gathered} 74\times5=\frac{88+80+83+74+s5}{5}\times5 \\ 74\times5=88+80+83+s5 \\ 74\times5-88-80-83-74=88+80+83+74-88-80-83-74+s5 \\ 74\times5-88-80-83-74=s5 \\ s5=74\times5-88-80-83-74=55 \end{gathered}

Then, Pedro must have a 55 score on the fifth test

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Answer:

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Step-by-step explanation:

i did use a calculator tho

5 0
3 years ago
Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
A parabola has a vertex at (4, 0) and passes through the point (6, 1). Which of the following is the equation of this parabola i
Doss [256]
Easy

y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a

thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
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3 years ago
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Ksivusya [100]

Answer:

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Step-by-step explanation:

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inna [77]

Answer:

D

Step-by-step explanation:

The function F(x) = \frac{1}{3}*4^x has value F(2) when x = 2 is substituted.

F(x) = \frac{1}{3}*4^x\\F(2) = \frac{1}{3}*4^2\\F(2) = \frac{1}{3}*16\\F(2) = \frac{16}{3}

7 0
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