Ask question

Ask question

All categories

3 years ago

15

A spider is trying to climb a wall that is 15 metres high. In each hour, it climbs up 3 metres, but falls back 2 metres. In how

many hours will it reach the top of the wall?

1 answer:

Eva8 [605]3 years ago

4 0

In 15 hours

That or 13 hours, if we don’t include the fall back for the last one tho I highly doubt that so go with 15

You might be interested in

Solve the system of equations algebraically

lora16 [44]

2x + 2y = 10
x + y = 5
x = 5 - y
Substitute for x in the other equation:-

(5 - y - 3)^2 + (y + 2)^2 = 16
(2 - y)^2 + (y + 2)^2 = 16
4 - 4y + y^2 + y^2 + 4y + 4 = 16
2y^2 + 8 = 16

2y^2 - 8 = 0
y^2 = 4

y = +/- 2

consider 2x + 2y = 10

when y = -2, 2x = 10 +4 giving x = 7
when y = 2, 2x = 10 - 4 giving x = 3

so solution is x = 7, y = -2 and x = 3, y=2.

8 0

3 years ago

Please help this is really important

Mama L [17]

I hope this helps you

6 0

3 years ago

B) if it takes the car 36 minutes to drive down the road, what will it's average speed be?

attashe74 [19]

Answer:

Incomplete question.

Step-by-step explanation:

You've only provided the time.

Please provide the distance of the road.

6 0

1 year ago

6+8d=7d solve for d.

Margarita [4]

Question -

6 + 8d = 7d

Solution-

6. = 7d - 8d

6. = -d

d. = -6

<h3>Verification </h3>

6 + 8(-6) = 7(-6)

6 - 48. = -42

-42. = -42

LHS= RHS

Hence value of d is -6

hope it helps

4 0

3 years ago

Read 2 more answers

Solve for x????????????????????

12345 [234]

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\: Concept }}}$

➣ Given two paris are linear pairs
➣ We know that sum of linear pairs is equal to 180⁰
➣ Linear :- Having the form of a line; straight or roughly straight; following a direct course.

$\large\underline{ \boxed{ \sf{✛\: Assumptions\:✛ }}}$

➣ let given two angles be p and q that is
➣ angle p is 3x-4
➣ angle q is 3x-8
➣ we have to find "x" in the given expressions

$\large\underline{ \boxed{ \sf{✰\: let's\:solve }}}$

$\rm\angle \: p + \angle \: q = 180 \degree \\$

★ Substituting values

$\rm { \pink➾ \:( 3x - 4) + (3x - 8) = 180} \\ \rm { \pink➾}arranging \: and \: solving \: like \: terms \\ \rm { \pink➾ \: 3x + 3x - 4 - 8 = 180} \\ \rm { \pink➾ \: 6x - 12 = 180} \\ \rm { \pink➾6x = 180 + 12}$

$\qquad \qquad\rm { \pink➾6x = 192} \\ \qquad\qquad\rm { \pink➾ \: x = \frac{ \cancel{192}}{ \cancel6} } \\ \qquad\qquad\rm { \pink➾x = 32}$

★ Hence the value

$\boxed{↪\underline{ \boxed{ \rm{\: x = 32\green✓}}}↩}$

$\rule{70mm}{2.9pt}$

Hope it helps !

5 0

2 years ago