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1 year ago

Differentiate each function with respect to x. Show steps

Mathematics

1 answer:

konstantin123 [22]1 year ago

4 0

The derivative of the function is f'(x) = 9x² tan x⁴ + 4x³(3x³ + 2) sec² x⁴.

<h3>What is the derivative of a function?</h3>

When a single-variable function exists at a given input value, its derivative is represented by the slope of the tangent line to the function's graph at that point.

The given function is f(x) =tan x⁴ · (3x³ + 2).

Differentiate the function with respect to x:

f'(x) = tan x⁴ · 9x² + (3x³ + 2) sec² x⁴· 4x³

= 9x² tan x⁴ + 4x³(3x³ + 2) sec² x⁴

Hence, the derivative of the function is

f'(x) = 9x² tan x⁴ + 4x³(3x³ + 2) sec² x⁴

Learn more about the derivatives:

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the perimeter of a square clock is 16 wholes and 6/9 inches.The perimeter of a rectangular clock is 16 wholes and 16/18 inches.W

sergejj [24]

6/9 and 16/18 is what we will mainly look at since the whole numbers are the same. the common denominator is 18. so you would multiply 6/9 by 2 (both the numerator and denominator multiplied by 2 ) therefore you will get 12/18. Which is bigger 12/18 or 16/18? 16/18 is bigger, therefore you would say sixteen and 6/9 is less than sixteen and 16/18. your answer should be this below. :)
16,6/9 < 16, 16/18.

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3 years ago

Can someone help me?

Tju [1.3M]

Answer:

Step-by-step explanation:

in table B if x = 1 y cannot equal both 1 and -1

no function can have x equal to two or more unique y's

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3 years ago

What is the equation of the line that passes through the points 15, nine and -2, nine

olasank [31]

Answer:

y=9

Step-by-step explanation:

y=mx+c

gradient of a horizontal line is 0

y=0x+9

y=9

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3 years ago

Pls help me

masha68 [24]

Answer:

Step-by-step explanation:

Volume of the figure = Base area * height

Base area:

Base area = area of trpezium + area of triangle

<u />

<u>Trapezium:</u>

a, b area the length of parallel sides and h is the height of trapezium.

a = 8 m ; b = 5 m & h = 3 m

$\boxed{ \text{ Area of trapezium = $\dfrac{(a +b)*h}{2} $}}$

$=\dfrac{(8+5)*3}{2}\\\\\\=\dfrac{13*3}{2}\\\\\\= \dfrac{39}{2}\\\\\\= 19.5 \ m^{2}$

<u>Triangle:</u>

height = 4 m & base = 8 m

$\boxed{\text{Area of triangle =$\dfrac{1}{2}*base*height$}}$

$=\dfrac{1}{2}*8*4\\\\\\= 4*4\\\\= 16 \ m^{2}$

Base area = 19.5 + 16

= 35.5 m²

Volume of the figure = Base area * height

= 35.5 * 14

= 497 m³

8 0

2 years ago

Two groups of students were asked how far they lived from their school. The table shows the distances in miles: Group A (distanc

iogann1982 [59]

The mean is equal for Group A and Group B.

<h2>Given </h2>

Two groups of students were asked how far they lived from their school.

The table shows the distances in miles:

Group A (distance in miles) 1 1.5 3.03 3.2 2.8 1.5 1.8 2.5 2.2

Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8

The mean of any data set or observation is equal to the sum of all the observations and divided by the number of observations.

The formula used to calculate the mean is;

$\rm Mean = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}$

The mean of group A is;

$\rm Mean = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}\\\\\rm GroupA \ mean = \dfrac{1 + 1.5 + 3.03 + 3.2 + 2.8 + 1.5 + 1.8 + 2.5 + 2.2}{9 }\\\\\rm Group A \ mean=\dfrac{ 19.53}{9}\\\\ Group A \ mean = 2.17$

The mean of group B is;

$\rm Mean = \dfrac{Sum \ of \ all \ observation}{Number \ of \ obrservation}\\\\\rm Group B \ mean = \dfrac{2 + 2.5 + 3.23 + 1.3 + 1.8 + 2.4 + 3 + 1.5 + 1.8}{9} \\\\Group B \ mean = \dfrac{19.53}{9}\\\\ Group B \ mean = 2.17$

Hence, the mean is equal for Group A and Group B.

To know more about Mean click the link given below.

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2 years ago