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Sati [7]
3 years ago
15

Hey I neee help with this I don’t understand for number 1 it’s w=? For number 2 it’s w=75 and for number 3 it’s w=26. Pls I need

help it’s due in 10 minutes I’ll mark brainliest possibly.

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

<em>1. W = 50 ft</em>

<em>2. L = 110 m</em>

<em>3. L = 61 m</em>

Step-by-step explanation:

<u>Area of a Rectangle</u>

Given a rectangle of width W and length L, its area is calculated by the formula:

A = W.L

We are given three rectangle-shaped figures and are required to find different measures as explained below.

1. Length L=94 ft, Area = 4,700 square ft

We'll find the width by solving for W:

\displaystyle W = \frac{A}{L}

\displaystyle W = \frac{4,700}{94}

W = 50 ft

2. A=8,250 square m, W=75 m

We'll find the length by solving for L:

\displaystyle L = \frac{A}{W}

\displaystyle L = \frac{8,250}{75}

L = 110 m

3. A=1,586 square m, W=26 m

We'll find the length by solving for L:

\displaystyle L = \frac{A}{W}

\displaystyle L = \frac{1,586}{26}

L = 61 m

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use this information for items 1-3. Aaron has $65 to rent a bike in the city . It costs $15 per hour to rent a bike. The additio
marissa [1.9K]

Answer:

<h2>You will ride for 4 hrs 8min</h2>

Step-by-step explanation:

What we are expected to solve for that the problem did not expressly state is most likely the number of hours that you could ride for an amount of $65.

firstly we need to model the inequality (equation) for this scenario.

the constant fee= $3 additional fee for helmet

3+15n\leq 65\\\\

We can now solve for n since the above inequality satisfies the condition presented in the problem statement.

 3+15n\leq 65\\\\15n\leq65-3\\\\ 15n\leq 62

Divide both sides by 15 to find n

n\leq 62/15\\\\n\leq 4hrs -8min

8 0
3 years ago
A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult
klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = \frac{Required outcomes}{Total possible outcomes}

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>


<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = \frac{n(Odd)}{Total} = \frac{10}{20} = \frac{1}{2} = 0.5


Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = \frac{n(5)}{Total} = \frac{4}{20} = \frac{1}{5} = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = \frac{2}{20}=\frac{1}{10}=0.1

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0
3 years ago
HEEELP MEEEE FIND THE CIRCUMFERENCE
Alex Ar [27]

Answer: 56.52

Step-by-step explanation:

4 0
3 years ago
Plz help i will mark brainliest
Alexus [3.1K]
2,3,and4 is 72
1 and 5 is 36
5 0
2 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
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