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Dima020 [189]
1 year ago
5

The pressure, P (in lbs/ft2 ), in a pipe varies over time. Five times an hour, the pressure oscillates from a low of 90 to a hig

h of 230 and then back to a low 90. The pressure at t = 0 is 90.
Question: Find a possible formula for P=f(t)
Mathematics
1 answer:
Lunna [17]1 year ago
7 0

P=160-70*cos(2π*(1/12)*t)

• Pressure in mathematics or physics is defined as force per unit area. The pressure exerted by a solid object which is resting on top of a solid surface is the weight divided by the area of the object . SI unit of force is Newton (N).

First, we find the amplitude by taking the difference between the peak values and dividing by two:

Amplitude=(230+90)/2=70

We can find the center value by either adding 70 to the minimum or subtracting 70 from the maximum:

90+70=160

230-70=160

This tells us that the Center Value=160

The frequency that we are operating at is given as:

f = 5/hour

so in minutes

f=5*(1/60)/minute=5/60=1/12 per minute

So, combining everything we get

P=160-70*cos(2π*(1/12)*t)

Learn more about Pressure here

brainly.com/question/26040104

#SPJ9

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Using the addition or subtraction formulas for sine or cosine.... sinasinb=(cos(a-b)-cos(a+b))/2
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Answer:

The answer w'll be obtained using formulas

cos(a+b) = cosacosb - sinasinb

cos(a-b) = cosacosb + sinasinb

Step-by-step explanation:

Using the trigonometric formula of addition and subtraction of cosine

cos(a+b) = cosacosb - sinasinb

cos(a-b) = cosacosb + sinasinb

w'll get the desired answer.

To be solve

L.H.S = R.H.S

sinasinb = (cos(a-b)-cos(a+b)/2

as we know that <u><em>cos(a+b) = cosacosb - sinasinb</em></u>

sinasinb = (cos(a-b) - (cosacosb -sinasinb))/2

as we know that <u><em>cos(a-b) = cosacosb + sinasinb</em></u>

sinasinb = ((cosacosb + sinasinb) - (cosacosb -sinasinb))/2

sinasinb = (cosacosb + sinasinb - cosacosb + sinasinb)/2

sinasinb = (2sinasinb)/2

sinasinb = sinasinb

hence L.H.S = R.H.S

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Step-by-step explanation:

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Step-by-step explanation:

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