The answer I got was a+2b
Answer:
b. w= 8x^2-2y / y
Step-by-step explanation:
Given:
(2*x^2)/y = (w+2)/4
Isolating w, we get:
w = (8*x^2)/y - 2
Multiplying and dividing the second term in the right-side of the equality by y, we get:
w = (8*x^2)/y - 2*y/y
Subtracting the fractions:
w = (8*x^2 - 2y)/y
Short Answer CRemarkYou may think there is no way to resolve this. Either of the first two look like they might work and you cannot be sure what you will get with the last two unless you know.
The answer is one of the last two. The equation cannot have just one or even a large number of complex numbers. When you are factoring a polynomial, the number of complex numbers must be even.
The complex root you have is x + 2i. Its partner is x - 2i
The complete equation would be
y = (x - 2i)(x + 2i) (x - 2)(x + 4)(x - 4)
I'll edit to add the graph.
Answer:
See explanation
Step-by-step explanation:
OK. Alvi is incorrect because he didn't add the measures of all 3 angles of the triangle, whereas Brian did. So, Brian is correct and Alvi needs to work on that kind of problem.
Emily could start with the quadratic equation
... (2x+5)(2x+6)=31
... 4x² +22x +30 = 31
And then subtract the right side to put it into standard form.
... 4x² +22x -1 = 0 . . . . . . corresponds to the first selection