The formula for the circumference of a circle is C = 2 pi r. Determine the circumference when the radius r is 10 cm.

The surface area of the square pyramid is 16 square inches. Find the value of x.

cluponka [151]

Answer:

x=6 2/5

Step-by-step explanation:

I don't know how to explain other than doing the math of (x*5)/2=16

3 0

3 years ago

Read 2 more answers

Select the correct answer. Which graph shows the solution region of this system of inequalities?

ELEN [110]

Since the values on both sides are different, hence graph of option C is correct.

<h3>What is inequality?</h3>

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

Solutions to inequality graphs

Inequalities are an equation that does not include only the equal sign.

The system of inequalities are;

$y \geq 2(1.3)^x\\\\y\leq -x^2 + 4x + 5$

The first function is an exponential function.

Since the values on both sides are different, hence graph of option C is correct.

Learn more on inequality here:

brainly.com/question/12089993

#SPJ1

4 0

2 years ago

How do you write an equation in slope intercept form for (-8.5,6.75), (3.33,-9.75)

Misha Larkins [42]

M = y2 - y1 / x2 - x1
= - 9.75 - 6.75 / 3.33 - ( -8.5 )
= - 16.5 / 11.83

=> y= - 16.5 / 11.83x +b
6.75 = - 16.5 / 11.83 ( -8.5) +b
6.75 = 11.86 +b
=> b = - 5.11

Answer : y= - 16.5 / 11.83x - 5.11

8 0

3 years ago

What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$