Givens
h = 10
b = 4x^y + 2xy^2
Formula
Area = 1/2 b * h
Solution
Substitute the givens into the formula
Area = 1/2 * 10 * (4x^2y + 2xy^2)
Area = 5 * (4x^2y + 2xy^2) What to do next? I would remove the brackets
Area = 5 * 4x^2y + 5 * 2xy^2
Area = 20x^2y + 10xy^2 <<<< Answer
Also possible is to take out more common factors.
The common factor of 4x^2y + 2xy^2 is 2xy and what is left over is 2x + y
So you would have Area = 5*2xy(2x + y)
If you have been given answers please list them.
Answer:
y= 25
i think
Step-by-step explanation:
Correct answer is : Area of triangle is
Solution:-
We can do it in 2 methods.
Method 1:-
Given that AB=6, BC=10 and m∠B = 120
Then area of triangle =
Let us assume AB is base and D is an altitude from C onto AB.
Then sin(60)=
CD = BC sin(60)
Hence height = =
Hence area of ΔABC = sq.units
Method2:-
Area of triangle =
Here a= BC=10, c=AB=6.
Hence area of triangle = sq.units
Answer:
co.: 14, -2, -5 var. terms: 14x,-2x,-5x con. terms: 9,8,1
Step-by-step explanation:
Answer:
102
Step-by-step explanation:
These angles are congruent due to corresponding angles thm
3x + 21 = 6x - 60
3x - 6x = -60 - 21
-3x = -81
x = 27
3x + 21
3(27) + 21
81 + 21
102