The general formula is:
![y = y_{o} + v_{o}t - \frac{1*g*t^{2} }{2}](https://tex.z-dn.net/?f=y%20%3D%20y_%7Bo%7D%20%2B%20v_%7Bo%7Dt%20-%20%20%5Cfrac%7B1%2Ag%2At%5E%7B2%7D%20%7D%7B2%7D%20)
-- (A)
Where g = 9.8 m/s/s
![v_{o}](https://tex.z-dn.net/?f=v_%7Bo%7D)
= 0
![y_{o}](https://tex.z-dn.net/?f=y_%7Bo%7D)
= 100
a)
Time=t=3s.
Plug-in the values in (A)
y = 100 -(1/2*9.8*3*3)
y = 100-44.1 = 55.9m
Height of the ball exactly after 3 seconds = 55.9m.
b)
At ground, y=0; Plug-in values in (A):
A=> 0 = 100 - (1/2* 9.8 * [tex]t_{2}[/text])
Therefore t = + 4.52 s and - 4.52 seconds.
As t cannot be negative, therefore:
Time when ball hits the ground =
4.52s
-i
Square piramid ,triangle prism.
Answer:
800 m
Step-by-step explanation:
Answer:
area:
Perimeter: 16x+12
Step-by-step explanation:
area :![(4x+3)^2](https://tex.z-dn.net/?f=%284x%2B3%29%5E2)
thats ![16x^2+24x+9](https://tex.z-dn.net/?f=16x%5E2%2B24x%2B9)
P: 4(4x+3)
thats 16x+12
Hope this helped you
<3
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