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OverLord2011 [107]
3 years ago
9

The ratio of pencil to rulers is 6:10. the are 21 pencils. how many rulers are there

Mathematics
1 answer:
Reika [66]3 years ago
8 0

There would be 35 rulers.

In order to solve this, use cross multiplication.

6/10 = 21/x -----> cross multiply

10*21 = 6*x

210 = 6x

35 = x

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Suppose you need to deliver 40 terabytes of data to your co-workers in Atlanta (200 km). You have an available 100 Mbps dedicate
Marat540 [252]

Answer: All data will be sent in 89.39 hours

Step-by-step explanation:

Data transfer rate: 100 Mbps=100 \frac{Mb}{s} ×\frac{1Tb}{1024^{2} Mb}×\frac{3600s}{h}=0.3433 \frac{Tb}{h}

The pigeon can fly 1000 km/day and it needs to fly 400 km (round trip).

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Time of round trip: 400 km÷\frac{1000km}{24h}=9.6 h

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8 0
3 years ago
How do i solve this? i need help
Korvikt [17]

A (103)(109)

=103*109

=(10*10*10)*(10*10*10*10*10*10*10*10*10)

=10*10*10*10*10*10*10*10*10*10*10*10

=1012

=1000000000000


c.1e+23

3 0
3 years ago
A car rental company charges a base fee of $30 per day to rent a car, along with an additional $0.18 per mile driven. If George
sladkih [1.3K]

George's cost per day is

... c = 30 + 0.18m

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3 0
3 years ago
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Which postulate proves that the two triangles are congruent?
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Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find <em>t</em>.

A(t)=A_{0}(1/2)^t^/^h

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For A_{0 let's just assume that there are 100 original  atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. <em>h</em> is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

74=100(1/2)^t^/^5^7^3^0

Now, solve. First, divide by 100.

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Take the log of everything

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Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the <em>t</em> and get

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Use your calculator to solve that giant mess for <em>t </em>and you'll get that <em>t</em> is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0
3 years ago
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