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Ivan
1 year ago
13

Assuming that the relationship between spring compression and height is quadratic, how far will the ball go at the highest setti

ng, which compresses the spring 3 cm ?
Physics
1 answer:
adelina 88 [10]1 year ago
5 0

Assuming that the relationship between spring compression and height is quadratic, 2.25m far will the ball go at the highest setting,  compresses the spring 3 cm

<h3>How do you calculate a compression spring's solid height?</h3>

The solid height, h1, of an unground spring is (n+1)d, where n is the number of coils and d is the wire diameter (including platings and coating) in inches. The height, h2, of ground but not squared springs is (n-1)d. The solid height, h3, of ground and squared springs is (n-0.75)d

When a spring is compressed, the potential energy is stored in the mechanical bonds between atoms, which may be thought of as little springs. The spring as a whole cannot decompress until it breaks, but little portions may when they fall off. The majority of the stored energy is used to decompress each little component.

learn more about  potential energy refer

brainly.com/question/14427111

#SPJ4

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A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically dr
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Answer:

Speed at the bottom of the roller coaster = 49.79 m/s

Explanation:

A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward.

We have to find the speed at the bottom.

Here the gravitational energy fully converts to kinetic energy, so we equate it.

Gravitational energy = m\times g\times h

Kinetic energy = 0.5 \times m\times v^{2}

m\times g\times h = 0.5 \times m\times v^{2}

9.8\times 126.5 = 0.5\times v^{2}

v^{2} = 2479.4

Velocity, v = 49.79 m/s

7 0
3 years ago
Tyra made the following bar graph shown to represent the relative distances of four different astronomical bodies from Earth.
Maslowich

Answer:

Please screenshot the bar graph so that i can answer.

Explanation:

8 0
3 years ago
Read 2 more answers
Why are some of the rocks on the moon older than the oldest known rocks on Earth?
Vadim26 [7]
Because the rocks of the moon is the first thing that is created by god he created first the outer then the erth
6 0
3 years ago
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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen
bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s} (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

7 0
4 years ago
A race car reaches the finish line and the driver slows down to come to a stop. If it takes the car 10 seconds to stop at a cons
boyakko [2]

Answer:

53.64 m/s

Explanation:

Applying,

a = (v-u)/t............. Equation 1

Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

make u the subject of the equation

u = v-at............. Equation 2

From the question,

Given: a = -12 mph/s = -5.364 m/s², t = 10 seconds, v = 0 m/s (comes to stop)

Substitute these values into equation 2

u = 0-(-5.364×10)

u = 0+53.64

u = 53.64 m/s

6 0
3 years ago
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