Answer:
The answer is 138.5
Explanation:
STEP 1:
The inductance per unit length of a coaxial transmission line is
L′=L<em>/ </em>I
=Ø/H
=μoI/2π In (b/a)
In this a is the radius of inner conductor
b is the radius of outer conductor
I is the coaxial transmission
μ is the magnetic permeability
Since the transmission of the charge exists in air, the value of the relative permeability is μr= I and permeability of free space is μo= 4π x 10-7 H/m . So the magnetic permeability will be
μ = μoμ r
μ =μ o(I) 4π x 10-7 H/m
L′= μoI/2π In (b/a)
= (4π x 10-7 ) (2)/2π In (10/5)
=2.77 x 10-7 H
STEP 2:
Obtain the magnetic energy stores in the magnetic field H of a volume of the coaxial transmission line containing a material with permeability μ, by using the formula given below:
Wm= 1/2 LI^2
= 1/2 (2.77x 10^-7 I^2
= 138.5 X 10^-9 I^2 J
Now we will simplify the equation
Wm= 185.5<em>I</em>^2 nJ
So, the magnetic energy stored in insulating medium is 185.5<em>I</em>^2 nJ
From context clues, I believe the correct answer is B) Red Dwarf!
<span>Use Charles' Law:
v1/T1 = v2/T2
88.2/(273+35) = v2/(273+155)
where v2 is the new volume.
I hope this helps!!!</span>
Soothing? I don't really know are there any choices?
