What is the route number for ( 697 and 129 )

Something that can not be used up or depleted

Jet001 [13]

Answer:

oxygen

Explanation:

as it is in the air it can't be depleted or used up

5 0

3 years ago

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How much force is needed to stop a body of mass 10kg

almond37 [142]

Answer:

Force of 100 N will be needed.

Explanation:

$Force, F = m \times g$

g is acceleration due to gravity

m is the mass

$F = (10 \times 10) \\ F = 100 \: newtons$

3 0

2 years ago

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Find the mass of a person who weighs 608 N

Anvisha [2.4K]

Answer:

$weight = mass \times accelaration \: due \: to \: gravity \\ 608 = x \times 10 \\ x = 608 \div 10 = 60.8 \\ mass = 60.8 \\ thank \: you$

7 0

2 years ago

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Marvin Martian is standing on planet Potatoine.

prisoha [69]

Answer:

W = 113.98 N

Explanation:

Given that,

Radius of Potatoine $R=6.4\times 10^6\ m$

Mass of Potatoine, $M=2\times 10^{24}\ kg$

Mass of Marvin, m = 35 kg

We need to find his weight on Potatoine. Weight of an object is given by :

W = mg

g is acceleration due to gravity, $g=\dfrac{GM}{R^2}$

So,

$W=\dfrac{GMm}{R^2}\\\\W=\dfrac{6.67\times 10^{-11}\times 35\times 2\times 10^{24}}{(6.4\times 10^6)^2}\\\\W=113.98\ N$

So, his weight on Potatoine is 113.98 N.

4 0

3 years ago

An experimentalist fires a beam of electrons, creating a visible path in the air that can be measured. The beam is fired along a

gtnhenbr [62]

Answer:

Velocity of the electron in the beam.

Radius of the circulating electrons due to the magnetic field.

Explanation:

We have a Mathematical expression for the force on a moving charge in a magnetic field as:

$F=q.v.B.sin \theta$ ...........................(1)

where:

q= charge on the particle in coulomb

v= velocity of the charge projected into the magnetic field

B= intensity of the magnetic field in tesla

$\theta$ = angle between the velocity and direction of magnetic field

For the forces on rotating mass we have the formula:

$F=m.\frac{v^2}{r}$ ..........................................(2)

where:

m= mass of the charged particle

v= velocity of projection of charge into the magnetic field

r= radius of the path traced by the charge in the magnetic field

From eq. (1) and (2) we can calculate the magnetic field .

Now,

Using Ampere's Law we have:

$B = \frac{\mu_0 .I}{2 \pi r}$

where:

I= current in the wire

$\mu_0=$ The permeability of free space.

r= radial distance from the current carrying wire( in this case it is same as the radius of the circular path)

4 0

3 years ago