Answer:
The correct answer is certain with probability equal to 1.
Step-by-step explanation:
Probability is a mathematical framework which helps us to analyze chance of the outcome in a particular experiment. The value of probability is given by the ratio of the possible outcomes favorable to a certain experiment to the total outcomes.
We say an event is certain when the probability is 1 and the probability is zero when the event is uncertain.
Here the experiment is picking a blue card from a bag containing all blue cards.
Possible outcomes are all the cards colored blue in the bag.
Total outcomes are also all the blue cards in the bag.
∴ The value of probability is 1 as the event is certain because if we pick a card from the bag containing only blue cards, it would certainly give us a blue card.
Largest 5-digit number is 54312 and is divisible by 6. The smallest 5 digit number is 12,345 and it's not divisible by 6
Answer:
first option
Step-by-step explanation:
To obtain ( f ○ g)(x) substitute x = g(x) into f(x) , that is
f(
)
=
( multiply numerator/ denominator by 2x to clear the fraction
= 
= 
Answer:
The answer is 22%.
Step-by-step explanation:
All you need to do to figure this out is to divide 36 by 8.
8/36=.222222
Hope this helps!
Answer:
A), B) and D) are true
Step-by-step explanation:
A) We can prove it as follows:

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that
. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then
.
C) Consider
. This set is orthogonal because
, but S is not orthonormal because the norm of (0,2) is 2≠1.
D) Let A be an orthogonal matrix in
. Then the columns of A form an orthonormal set. We have that
. To see this, note than the component
of the product
is the dot product of the i-th row of
and the jth row of
. But the i-th row of
is equal to the i-th column of
. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then
E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.
In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set
and suppose that there are coefficients a_i such that
. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then
then
.