Given:
The first two terms in an arithmetic progression are -2 and 5.
The last term in the progression is the only number in the progression that is greater than 200.
To find:
The sum of all the terms in the progression.
Solution:
We have,
First term : ![a=-2](https://tex.z-dn.net/?f=a%3D-2)
Common difference : ![d = 5 - (-2)](https://tex.z-dn.net/?f=d%20%3D%205%20-%20%28-2%29)
![= 5 + 2](https://tex.z-dn.net/?f=%3D%205%20%2B%202)
![= 7](https://tex.z-dn.net/?f=%3D%207)
nth term of an A.P. is
![a_n=a+(n-1)d](https://tex.z-dn.net/?f=a_n%3Da%2B%28n-1%29d)
where, a is first term and d is common difference.
![a_n=-2+(n-1)(7)](https://tex.z-dn.net/?f=a_n%3D-2%2B%28n-1%29%287%29)
According to the equation,
.
![-2+(n-1)(7)>200](https://tex.z-dn.net/?f=-2%2B%28n-1%29%287%29%3E200)
![(n-1)(7)>200+2](https://tex.z-dn.net/?f=%28n-1%29%287%29%3E200%2B2)
![(n-1)(7)>202](https://tex.z-dn.net/?f=%28n-1%29%287%29%3E202)
Divide both sides by 7.
![(n-1)>28.857](https://tex.z-dn.net/?f=%28n-1%29%3E28.857)
Add 1 on both sides.
![n>29.857](https://tex.z-dn.net/?f=n%3E29.857)
So, least possible integer value is 30. It means, A.P. has 30 term.
Sum of n terms of an A.P. is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Substituting n=30, a=-2 and d=7, we get
![S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D%5Cdfrac%7B30%7D%7B2%7D%5B2%28-2%29%2B%2830-1%297%5D)
![S_{30}=15[-4+(29)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B%2829%297%5D)
![S_{30}=15[-4+203]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B203%5D)
![S_{30}=15(199)](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%28199%29)
![S_{30}=2985](https://tex.z-dn.net/?f=S_%7B30%7D%3D2985)
Therefore, the sum of all the terms in the progression is 2985.
The last resort because you have no more options
Answer:
I know this isn't a real question,but you would have 11 dead bodies,I think
Step-by-step explanation:
8 will go into 66 , 8.25 times
Answer:
Step-by-step explanation: