Write the equation of a line whose slope is 2/3 and crosses the y axis at (0, -5)
1 answer:
The equation of line with slope 2/3 and crosses the y axis at (0, -5) is:
Step-by-step explanation:
We will use the slope intercept form of the equation to make an equation of the given line
The slope-intercept form is:
Here m is the slope and b is the y-intercept
Given
m = 2/3
Putting the value of slope
The y intercept is -5 so we will put in the equation
The equation of line with slope 2/3 and crosses the y axis at (0, -5) is:
Keywords: Equation of line, slope-intercept form
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Answer:
Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.
To prove: Point A,D,P are collinear.
Proof:
→Case 1. When vertices A and P are opposite side of Base BC.
In Δ ABD and Δ ACD
AB= AC [Given]
AD is common.
BD=DC [median of a triangle divides the side in two equal parts]
Δ ABD ≅Δ ACD [SSS]
∠1=∠2 [CPCT].........................(1)
Similarly, Δ PBD ≅ Δ PCD [By SSS]
∠ 3 = ∠4 [CPCT].................(2)
But, ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]
2 ∠2 + 2∠ 4=360° [using (1) and (2)]
∠2 + ∠ 4=180°
But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.
So, point A, D, P lies on a line.
CASE 2.
When ΔABC and ΔPBC lie on same side of Base BC.
In ΔPBD and ΔPCD
PB=PC[given]
PD is common.
BD =DC [Median of a triangle divides the side in two equal parts]
ΔPBD ≅ ΔPCD [SSS]
∠PDB=∠PDC [CPCT]
Similarly, By proving ΔADB≅ΔADC we will get, ∠ADB=∠ADC[CPCT]
As PD and AD are medians to same base BC of ΔPBC and ΔABC.
∴ P,A,D lie on a line i.e they are collinear.
Answer:
Part A)
1) The graph in the attached figure N 1
2) The coordinate rule is (x,y) -----> (x,y+10)
3) The translation of the function up 10 units means that the initial deposit is $60 instead of $50
Part B)
1) The graph in the attached figure N2
2) The coordinate rule is (x,y) -----> (x-10,y)
3) The translation of the function right 10 units means that the initial deposit is equal to $10
Part C)
1) In each translation, the slope is the same (m=5) are parallel lines
2) The vertical translation would be up 40 units
Step-by-step explanation:
we have
where
f(x) --> represents Jeremy's account balance
x ---> the time in years
Part A)
The translation of the function is up 10 units.
The rule of the translation is equal to
(x,y) -----> (x,y+10)
so
The new function will be
The graph in the attached figure N 1
The translation of the function up 10 units means that the initial deposit is $60 instead of $50
Part B)
The translation of the function is right 10 units.
The rule of the translation is equal to
(x,y) -----> (x-10,y)
so
we have
----> function Part A
The new function will be
The graph in the attached figure N 2
The translation of the function right 10 units means that the initial deposit is equal to $10
Part C)
1. Look at the translations, what characteristic of the graph stayed the same in each translation?
In each translation, the slope is the same
The slope m is equal to m=5
Are parallel lines
2. Look at the original graph and the graph of the translation right 10 units. What vertical translation of the graph in Part B would put the graph back to its original position?
we have
The vertical translation would be up 40 units
The rule of the translation is equal to
(x,y) -----> (x,y+40)
so
The new function will be
