Answer:
The question is incomplete, below is the complete question "The electric potential difference between the ground and a cloud in a particular thunderstorm is . What is the magnitude of the change in the electric potential energy of an electron that moves between the ground and the cloud?"
Answer:
Explanation:
data given,
Potential difference,V=3.0*10^9V
charge on an electron, q=1e.
Recall that the relationship between potential difference (v), charge(Q) and the potential energy(U) is expressed as
from the question, we asked to determine potential energy given the charge and the potential difference.
Hence if we substitute values into the equation, we arrive at
Hence the magnitude of the change in the electric potential energy of an electron that moves between the ground and the cloud is
Answer:
K ∅ = 1.48 Wb
Explanation:
given data
EA=(82 V/A)
speed = 1,710 rpm
RA = 9Ω
Rad j = 6Ω
RF = 30Ω
voltage VT = 97 V
to find out
Kϕ for the motor in Wb
solution
first we get here shunt field current
shunt field current = ............1
shunt field current =
shunt field current IF = 3.233 A
and
now we get here induced emf for field current that is
induced emf = 82 IF
induced emf = 82 × 3.233
induced emf = 265.133 V
and induced emf EA is also express as
induced emf EA = K∅ω .....................2
EA = K ∅ ×
put here value
265.133 = K ∅ ×
solve we get
K ∅ = 1.48 Wb
Answer and Explanation:
There are different characteristics for the material of friction surfaces that are given bellow.
- The coefficient of friction of the material of friction surface should be very high.
- Coefficient of friction throughout the surface should be uniform.
- The material should have impacted by moisture and oil
- Material should have great ability to bear high temperature
- Material should have high resistance and high heat of conductivity
Answer:
a mass of water required is mw= 1273.26 gr = 1.27376 Kg
Explanation:
Assuming that the steam also gives out latent heat, the heat provided should be same for cooling the hot water than cooling the steam and condense it completely:
Q = mw * cw * ΔTw = ms * cs * ΔTw + ms * L
where m = mass , c= specific heat , ΔT=temperature change, L = latent heat of condensation
therefore
mw = ( ms * cs * ΔTw + ms * L )/ (cw * ΔTw )
replacing values
mw = [182g * 2.078 J/g°C*(118°C-100°C) + 118 g * 2260 J/g ] /[4.187 J/g°C * (90.7°C-39.4°C)] = 1273.26 gr = 1.27376 Kg