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HACTEHA [7]
3 years ago
11

Starting with a context diagram, draw as many nested DFDs as you consider necessary to represent all the details of your times p

ortal system described in the following narrative. You must draw at least a context and level-1 DFD. In drawing these diagrams, if you discover that the narrative is incomplete, make up reasonable explanations to complete the story.
Engineering
1 answer:
neonofarm [45]3 years ago
6 0

The larvae of mosquitoes live in water and provide food for fish and other wildlife, including larger larvae of other species such as dragonflies. The mosquito larvae themselves consume a lot of organic matter in wetlands, helping recycle nutrients back into the ecosystem.

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1. A car engine transfers 3000J in 20 seconds. What is the power generated by the engine?
Scorpion4ik [409]

Answer:

  150 W

Explanation:

Power is energy per unit time. The power generated by the engine is ...

  (3000 J)/(20 s) = 150 J/s = 150 W

The engine generated 150 watts.

3 0
3 years ago
Gina is about to use a fire extinguisher on a small fire. What factor determines the
Effectus [21]

Answer:

Each portable fire extinguisher should only be used for its specific type of fire. Class A extinguishers could cause a Class B fire to spread or electrocution in a Class C fire. A Class B extinguisher could fail to completely extinguish a Class A fire, causing the flame to re-ignite later.

7 0
3 years ago
The article provides information by using a list. What does it list? A. Thanksgiving food B. places where clams can be found C.
Gelneren [198K]

Answer:

C

Explanation:

7 0
4 years ago
What is the De Broglie wavelength of an electron under 150 V acceleration?
yanalaym [24]

Answer:

0.1 nm

Explanation

Potential deference of the electron is given as V =150 V

Mass of electron m=9.1\times 10^{-31}

Let the velocity of electron = v

Charge on the electron =1.6\times 10^{-19}C

plank's constant h =6.67\times 10^{-34}

According to energy conservation eV =\frac{1}{2}mv^2

v=\sqrt{\frac{2eV}{M}}=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 150}{9.1\times 10^{-31}}}=7.2627\times 10^{-6}m/sec

Now we know that De Broglie wavelength \lambda =\frac{h}{mv}=\frac{6.67\times 10^{-34}}{9.1\times 10^{-31}\times 7.2627\times10^6 }=0.100\times 10^{-9}m=0.1nm

4 0
3 years ago
Read 2 more answers
Can you gift points in this if yes please send some
dimaraw [331]
No, you can’t sorry :(
4 0
4 years ago
Read 2 more answers
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