Answer:
See explaination
Explanation:
This is going to require diagrams, please kindly see attachment for the detailed step by step solution of the given problem.
Answer: Either your computer is malfunctioning or it is glitched and still thinks you only have 2. Also good job
Explanation: Leave a brainliest it helps
Answer:
a) The rate at which the cube emits radiation energy is 704.48 W
b) The spectral blackbody emissive power is 194.27 W/m²μm
Explanation:
Given data:
a = side of the cube = 0.2 m
T = temperature = 477°C
Wavelength = 4 µm
a) The surface area is:

According Stefan-Boltzman law, the rate of emission is:

b) Using Plank´s distribution law to get the spectral blackbody emissive power.

Answer:
2074.2 KW
Explanation:
<u>Determine power developed at steady state </u>
First step : Determine mass flow rate ( m )
m / Mmax = ( AV )₁ P₁ / RT₁ -------------------- ( 1 )
<em> where : ( AV )₁ = 8.2 kg/s, P₁ = 0.35 * 10^6 N/m^2, R = 8.314 N.M / kmol , </em>
<em> T₁ = 720 K . </em>
insert values into equation 1
m = 0.1871 kmol/s ( mix )
Next : calculate power developed at steady state ( using ideal gas tables to get the h values of the gases )
W( power developed at steady state )
W = m [ Yco2 ( h1 - h2 )co2
Attached below is the remaining part of the detailed solution
Answer:
Copy MATLAB code to plot the magnitude of magnetic field strength with respect to z on the axis of solenoid:
z=-20:0.01:20;
H=120.*(((20-(2.*z))./sqrt((20-(2.*z)).^2+100))+((20+(2.*z))./sqrt((20+(2.*z)).^2+100)));
plot(z,H)
title('plot of |H| vs z along the axis of solenoid')
ylabel('Magnitude of magnetic field 'H")
xlabel('position on axis of solenoid 'z")
Explanation:
full explanation is attached as picture and the resultant plot also.