Answer:
Ksp = 2.74 x 10⁻⁵
Explanation:
The solubility equilibrium for Ca(OH)₂ is the following:
Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)
I 0 0
C + s + 2s
E s 2s
According to the ICE table, the expression for the solubility product constant (Kps) is:
Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³
Then, we calculate Ksp from the solubility value (s):
s = 0.019 M
⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵
Answer:
2.232 g/L
Explanation:
Assuming 1 mol, volume at STP is 22.4 L so you simply divide 50g by 22.4 L to get density
Answer: C. growth
Explanation: because why not
Answer:
MgI₂, MgO, PbI₄, PbO₂
Explanation:
For an ionic compound to be formed, it must be neutral, that is the total positive charge must be equal to the total negative charge.
Mg²⁺ and I⁻: The neutral ionic compound requires 1 Mg²⁺ and 2 I⁻ and the resulting empirical formula is MgI₂.
Mg²⁺ and O²⁻: The neutral ionic compound requires 1 Mg²⁺ and 1 O²⁻ and the resulting empirical formula is MgO.
Pb⁴⁺ and I⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 4 I⁻ and the resulting empirical formula is PbI₄.
Pb⁴⁺ and O²⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 2 O²⁻ and the resulting empirical formula is PbO₂.
Answer:
The one that gives you more energy!
Explanation: