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-Dominant- [34]
3 years ago
8

Cierta cantidad de gas ocupa 20 litros sometido a una presión de 1,5 atmósferas. Si lo comprimimos hasta 6 atmósferas, ¿qué volu

men ocupará?
Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Respuesta:

5 L

Explicación:

Paso 1: Información provista

  • Presión inicial (P₁): 1,5 atm
  • Volumen inicial (V₁): 20 L
  • Presión final (P₂): 6 atm

Paso 2: Calcular el volumen final del gas

Si asumimos temperatura constante y comportamiento ideal, podemos calcular el volumen final del gas (V₂) usando la Ley de Boyle.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1,5 atm × 20 L / 6 atm = 5 L

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Determine the theoretical yield and the percent yield if 21.8 g of K2CO3 is produced from reacting 27.9 g KO2 with 57.0 g CO2. T
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Answer:

26.9 g

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Explanation:

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2 moles of CO2 yields 2 moles of K2CO3

1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3

Hence the limiting reactant is KO2

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Percent yield = actual yield/theoretical yield × 100

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3 years ago
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Answer:

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