The solution could be described like a saturated and concentrated solution.
<h3>Solutions</h3>
Dissolution of solutions can occur in certain ways. These ways depend on the solvent dilution coefficient and the amount of solute.
If the amount of solute is less than the solvent can dissolve, the solution is unsaturated.
If the amount of solute is exactly the same, the solution is saturated.
If the amount is greater, the solution is supersaturated.
So, since the amount of solute is exactly equal to the amount that the solvent can dissolve, the solution is saturated and concentrated.
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Given :
A chemical compound
.
To Find :
Fix the formula for
and write the full correct formula.
Solution :
We know, Potassium( K ) and Fluorine( F ) both have a valency of 1 i.e potassium can donate one electron and Fluorine can accept one electron only.
So, the chemical formula
is wrong because no element has filled electron.
Therefore, to stabilise the molecule, 1 Potassium atom should make a bond from 1 Fluorine i.e KF ( correct formula ) .
Hence, this is the required solution.
Answer: HA + H2O ⇌ H3O+ + H- (option #4)
Explanation: Since the acid is weak you have to use a ⇌ (equilibrium) sign. Equilibrium is denoted in a chemical equation by the ⇌ symbol. Also, when any acid dissolves into water, it produces hydronium (H3O+ or H+). Therefore, the fourth chemical reaction is your answer.
Answer:

Explanation:
The activation energy represents the energy barrier that reagents must pass to transform into products (or products to transform into reagents in a reverse reaction)
For any reaction, the change in enthalpy is related to the activation energy by the equation

So, the activation energy for the reverse reaction is

Answer:
HCl
Explanation:
The best solvent for NaF is a polar liquid. The only liquid having a significant dipole moment among the options is HCl due to the large electro negativity difference between hydrogen and chlorine.
The polar solvent can interact with the NaF via its dipoles such that the NaF dissolves due to ion-dipole interaction.