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3 years ago

find the mean, median, and mode of he data set. round to the nearest tenth. 7, 5, 4, 2, 1, 1, 2, 3, 5, 4, 5

2 answers:

5 0

Hello!

Mean: 7 + 5 + 4 + 2 + 1 + 1 + 2 + 3 + 5 + 4 + 5 = 39

39 ÷ 11 = 3.5

The mean is 3.5

~~~~~~~~~~~~

Median: 1, 1, 2, 2, 3, 4, 4, 5, 5, 5, 7 - Which number is in the center?

The median is 4

~~~~~~~~~~~~~~~~~

Mode: Which number appears most often?

The mode is 5.

Hope I helped! :3

SashulF [63]3 years ago

4 0

Hello!

First you need to list the numbers from least to greatest

1, 1, 2, 2, 3, 4, 4, 5, 5, 5, 7

To find the mean you add all the numbers up and divide the sum by the amount of numbers added

1 + 1 + 2 + 2 + 3 + 4 + 4 + 5 + 5 + 5 + 7 = 39

39 / 10 = 3.9

The mean is 3.9
------------------------------------------------------------------------------------------------------
To find the median you find the number in the middle

The median is 4
------------------------------------------------------------------------------------------------------
The mode is the number that appears the most

The mode is 5

Hope this helps!

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3 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

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3 years ago

I need help 44points If u help me

Ira Lisetskai [31]

You should also try wolframalpha.com it can also help u. Just send this exact picture and then they'll help you

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3 years ago

Ej’s bikes rents bikes for $18 plus $5 per hour.Marrisa paid $48 to rent a bike.For how many hours did she rent the bike?

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Marrisa rented the bike for 6 hours

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2 years ago

Ralph and Jody go to the store to buy chips and candy bars. Ralph buys 3 bags of potato chips and 4 candy bars for 375 cents. Jo

s2008m [1.1K]

3x+4y = 375
6x+ 4y= 600
-------------------
6x-3x = 600 - 375

3x=225
x=225:3
x=75 cents

3*x+4y= 375
3*75+4y=375
225 +4y = 375
4y=375-225
4y=150
y=150:4
y=37,5 cents

the price is 75+37,5=112,5 cents for one bag of potato chips and one candy bar

3 0

3 years ago