Answer:
The answer to the question is
The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph
Step-by-step explanation:
Speed of bus in the first third distance = v kph
Speed of bus for the remaining two thirds = 1.2 v kph
To solve the question, we note that speed = distance/time
therefore time = distance/speed
Let the distance of the destination be D, then
Normal duration at speed v = D/v
Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v
=
= (8/9)×D/v
Therefore the actual duration is 8/9 times the normal duration
Answer: multply
Step-by-step explanation:
As per the problem,
Rhonda bought a new laptop for $800.
The laptop depreciates, or loses, 20% of its value each year.
The value of the laptop at a later time can be found using the formula

Here we have
P=$800
r=20%=0.20
t=2 years
Substitute the values in equation (1) we get

The laptop be worth in two years will be $512.