Question

The perpendicular line equation given y=7x-2 and passes through -4,6

Answer 1

The equation of the perpendicular line is y = -1/7(x + 4) + 6

How to determine the perpendicular line equation?

From the question, we have the following parameters that can be used in our computation:

y = 7x - 2

Also, from the question;

We have the following points

The point is given as

Point = (-4, 6) i.e.  (x, y) = (-4, 6)

The equation of a line can be represented as

y = mx + c

Where

Slope = m

By comparing the equations, we have the following

m = 7

This means that the slope is 7

The slopes of perpendicular lines are opposite reciprocals

This means that the slope of the other line is -1/7

The equation of the line is then calculated as

y = m(x - x₁) +y₁

Where

m = -1/7

(x₁, y₁) = (-4, 6)

So, we have

y = -1/7(x + 4) + 6

Hence, the line has an equation of y = -10/3x + 1

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brainly.com/question/4074386

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