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Rudik [331]
1 year ago
5

Find the area of a triangle whose sides are 3cm,6cm and 7cm

Mathematics
1 answer:
nadya68 [22]1 year ago
4 0

Answer:

See below

Step-by-step explanation:

It is NOT  a RIGHT triangle so you <u>cannot use</u>   1/2 b * h

 but you can use Heron's Formula

Area = sqrt( s (s-a)(s-b)(s-c) )

s = semi- perimeter =   (3+6+7)/2 = 8

Area = sqrt ( 8 ( 8-3)(8-6)(8-7) )   = sqrt ( 80) = 8.9 cm^2

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HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?
tangare [24]

Answer:

y=-(x-7)(x+3)

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

y=-(x+3)(x-7) but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is y=a(x-h)^2+k.

This is called vertex form because it gives you the vertex is (h,k).

We are given that (h,k)=(2,25) which makes our equation:

y=a(x-2)^2+25.

We can find the value of a by plugging in the x-intercept (7,0) for (x,y) into:

y=a(x-2)^2+25

0=a(7-2)^2+25

0=a(5)^2+25

Subtract 25 on both sides:

-25=a(5)^2

-25=a(25)

Divide both sides by 25:

\frac{-25}{25}=a

-1=a.

So the equation for the quadratic is:

y=-1(x-2)^2+25

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

y=-1(x-2)(x-2)+25

y=-1(x^2-2x-2x+4)+25

y=-1(x^2-4x+4)+25

y=-x^2+4x-4+25

y=-x^2+4x+21

Factor out -1:

y=-(x^2-4x-21)

WE need to find two numbers that multiply to be -21 and add to be -4:

y=-(x-7)(x+3)

8 0
3 years ago
Read 2 more answers
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Answer: the Answer is 33
8 0
2 years ago
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LenaWriter [7]
D is the correct answer
x+5=10: subtract 5 from both sides the 5 will cancel out leaving x=5
x+5=10
-5 -5
x=5
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3 years ago
How many terms are in the arithmetic sequence 9, 2, −5, . . . , −187?
Fantom [35]
9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;a_1=9\\&#10;d=-7\\&#10;a_n=-187&#10;\end{cases}&#10;\\\\\\&#10;-187=9+(n-1)(-7)\implies -187=9-7n+7&#10;\\\\\\&#10;7n=9+7+187\implies 7n=203\implies n=\cfrac{203}{7}\implies \boxed{n=29}
4 0
3 years ago
Last summer there were 88 players at coach rodriguez basketball camp. this year there are 125% of this number of players. how ma
ludmilkaskok [199]
To determine the number of those who joined the basketball camp this year, we just have to multiply the number of those who joined last year by the decimal equivalent of the percentage given. That is,
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Therefore, there are a total of 110 players for this years basketball camp. 
6 0
3 years ago
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