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Eddi Din [679]
3 years ago
12

What is the rationalizing factor of √3? ​

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

±  \sqrt{3}  \:  \: ( \sqrt{3}  \:  \: or \:  \:  -  \sqrt{3} )

Step-by-step explanation:

\sqrt{3}  \times  \sqrt{3}  = 3 \:  \: (rationalize)

\sqrt{3}  \times ( -  \sqrt{3} ) =  - 3

The rationalizing factor of \sqrt{ 3}

is \boxed{\green{\sqrt{3}  \:  \: or \:  \:  -  \sqrt{3}}}

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We are given

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Vertical asymptotes:

Firstly, we will factor numerator and denominator

we get

y=\frac{(x-1)(x-3)}{(x-3)(x+3)}

We can see that (x-3) is common in both numerator and denominator

so, we will only set x+3 to 0

and then we can find vertical asymptote

x+3=0

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Hole:

We can see that (x-3) is common in both numerator and denominator

so, hole will be at x-3=0

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Horizontal asymptote:

We can see that degree of numerator is 2

degree of denominator is also 2

for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator

and we get

y=1

now, we can draw graph

Graph:


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Attached is a screenshot.

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