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Sidana [21]
1 year ago
14

What are two qualities of metals?​ Describe each

Chemistry
2 answers:
Jlenok [28]1 year ago
4 0

Answer:Typical physical properties of metals : high melting points. good conductors of electricity. good conductors of heat.

Explanation:

Brums [2.3K]1 year ago
3 0
High melting and boiling points, solid at room temperature, malleable, hard , shiny, good conductors
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So2−3(aq)→so2−4(aq) (basic solution) express your answer as a chemical equation. identify all of the phases in your answer. so32
alexira [117]

Answer:

SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

Explanation:

The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:

Chemical equation: SO_{3}^{2-}(aq.)\rightarrow SO_{4}^{2-}(aq.)

Balance H and O in basic medium: SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)

Balance charge: SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

Balanced chemical equation:

SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}

6 0
3 years ago
Is AgNO3 soluble or insoluble in water?
gtnhenbr [62]

Answer:

Silver Nitrate is very soluble in water.

5 0
2 years ago
The pH of a solution in which the concentration of H+ is 0.010M will be:
shusha [124]

B: 2

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7 0
2 years ago
Which bent shape has more repulsion and a smaller bond angle?<br> bent 6A<br> bent 5A
Step2247 [10]
Bent 6A is the answer
8 0
3 years ago
In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro
Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

Explanation :

Molality : It is defined as the number of moles of solute present in kilograms of solvent.

Formula used :

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}

Solute is, NaBr and solvent is, water.

Given:

Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}

\text{Mass of NaBr}=18.3g

Thus, the mass of sodium bromide added should be, 18.3 grams.

6 0
3 years ago
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