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iVinArrow [24]
3 years ago
13

Energy is needed to break bonds in chemical reactions

Chemistry
1 answer:
NeX [460]3 years ago
7 0

Answer:

This is True

Explanation:

When a chemical reaction occurs, molecular bonds are broken and other bonds are formed to make different molecules. For example, the bonds of two water molecules are broken to form hydrogen and oxygen. Energy is always required to break a bond, which is known as bond energy.

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A biochemist would most likely study what ?
Molodets [167]

Answer:

Biochemists study chemical processes and chemical transformations in living organisms. Biochemists study DNA, proteins and cell parts. The word "biochemist" is a portmanteau of "biological chemist."

Explanation:

6 0
2 years ago
125 K = °C<br> A) 146<br> B)-146<br> C)398<br> D)-398
Mrrafil [7]
125 Kelvin turns into -146 C
4 0
2 years ago
Read 2 more answers
The solubility of CO2 in water is 0.161 g/100 mL at 20oC and a partial pressure of CO2 of 760 mmHg. What partial pressure of CO2
Schach [20]

<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg

<u>Explanation:</u>

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

The equation given by Henry's law is:

C_{CO_2}=K_H\times p_{CO_2}       ......(1)

where,

C_{CO_2 = solubility of carbon dioxide in water = 0.161 g/100 mL

K_H = Henry's constant = ?

p_{CO_2} = partial pressure of carbon dioxide = 760 mmHg

Putting values in equation 1, we get:

760mmHg=K_H\times 0.161g/100mL\\\\K_H=\frac{760mmHg}{0.161g/100mL}=4720.5g.mmHg/100mL

Now, calculating the pressure of carbon dioxide using equation 1, we get:

C_{CO_2 = solubility of carbon dioxide in water = 0.886 g/100 mL

K_H = Henry's constant = 4720.5 g.mmHg/100 mL

p_{CO_2} = partial pressure of carbon dioxide = ?

Putting values in equation 1, we get:

p_{CO_2}=4720.5g.mmHg/100mL\times 0.886g/100mL=4182.4mmHg

Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg

4 0
3 years ago
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonatio
Over [174]

Answer:

Most substituted alkene is produced as a major product

Explanation:

  • Dehydration of 3-methyl-2-butanol proceeds through E1 mechanism to form alkenes.
  • Most substituted alkene is produced as major product because of presence of highest number of hyperconjugative hydrogen atoms corresponding to the produced double bond (Saytzeff product).
  • Here, a H-shift also occurs in one of the intermediate step during dehydration to produce more stable tertiary carbocation.
  • Reaction mechanism has been shown below.

4 0
2 years ago
Consider the following statements.
Vsevolod [243]

Answer: B and C only

Explanation:

3 0
3 years ago
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