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2 years ago

Energy is needed to break bonds in chemical reactions

Chemistry

1 answer:

NeX [460]2 years ago

7 0

Answer:

This is True

Explanation:

When a chemical reaction occurs, molecular bonds are broken and other bonds are formed to make different molecules. For example, the bonds of two water molecules are broken to form hydrogen and oxygen. Energy is always required to break a bond, which is known as bond energy.

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Weather... weather is the obvious answer

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Pls help me !!!! Is for chemistry

Sphinxa [80]

Answer:

Explanation:

1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L

2) Molar mass of NaCl is 23+35 = 58g

Molarity = (0.5/58)/0.075 = 0.115 Mol/L

3) Molar mass of $Li_{2}SO_{4}$ = 7x2 + 32 + 16x2 = 78g

Molarity = (734/78)/0.875 = 10.754 Mol/L

5) Molar mass of $Pb(C_{2}H_{3}O_{2})_{4}$

= 207.2 + ((12x2) + (1x3) + (16x2))x4

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6) Both are the same.

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Molarities of the solutions are the same.

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One important sugar that results from photosynthesis is cellulose. True or false

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Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesi

tamaranim1 [39]

Initial concentration of magnesium nitrate M1 = 2.13 M

Initial volume of magnesium nitrate, MgNO3 V1 = 1.24 L

Final concentration of MgNO3, M2 = 1.60 M

Let the final volume of MgNO3 upon dilution be V2

Formula to use:

M1*V1 = M2*V2

V2 = M1*V1/M2

= 2.13 M * 1.24 L/1.60 M = 1.65 L

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How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)

jonny [76]

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

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2 years ago