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2 years ago

HELPPPPPPPPPPPPPPPPP ASAP!!!!!!!!!!!!!!!!!!

Chemistry

2 answers:

Gre4nikov [31]2 years ago

8 0

Answer:

i think that b is the awnser sorry if im wrong

Explanation:

Leto [7]2 years ago

5 0

Answer:

i think that b is the awnser sorry if im wrong

Explanation:

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For the following formula, C4H9Cl, calculate the IHD and select all the types of unsaturation that might be present in the molec

Airida [17]

Answer:

The IHD = 0

There is no unsaturation in the compound C4H9Cl

Explanation:

IHD = Index for Hydrogen Deficiency .It determines total number of unsaturation or Pi- bond present in the molecule.It is calculated using the formula:

For Molecule:

$C_{c}H_{h}O_{o}N_{n}X_{x}$

Here . C = carbon

H = Hydrogen

O = Oxygen

N = Nitrogen

X = Halogen

The IHD is calculated as :

$\frac{2c-h-x+n+2}{2}$ ...............(1)

For example :

C4H8O2

Here c = 4 , h = 8 , o = 2 .

n = x=0

Put the value in equation (1) and find IHD

$\frac{2(4)-8-0+0+2}{2}$

$\frac{8-8+2}{2}$

$\frac{2}{2}$

IHD = 1

For C4H9Cl

c = 4 , h = 9 and x = 1

IHD for this molecule can be calculated as :

$\frac{2c-h-x+n+2}{2}$

$\frac{2(4)-9-1+2}{2}$

$\frac{8-9-1+2}{2}$

= 0

This means there is no unsaturation in the molecule.

Each bond is sigma bond and properly saturated.

5 0

2 years ago

5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H

cricket20 [7]

We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572. That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0

3 years ago

Why was UwU createdwwwwwwwwwwwwwwwwwwwwwwwwwwwww

photoshop1234 [79]

a typable representation of emotion

5 0

1 year ago

Which equation shows how to solve for enthalpy of solution based on the information in tables?

Tatiana [17]

Answer: B. triH sol Mgl2= -triHlat+ triHhydr Mg^2+ 2triHhydr^l-

Explanation:

Just did it and it was right