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PIT_PIT [208]
3 years ago
6

HELPPPPPPPPPPPPPPPPP ASAP!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

i think that b is the awnser sorry if im wrong

Explanation:

Leto [7]3 years ago
5 0

Answer:

i think that b is the awnser sorry if im wrong

Explanation:

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Complete the acid-base reaction between butyric acid HC4H7O2 and potassium hydroxide KOH.
Lilit [14]

An acid-base reaction or a neutralization reaction is a <u>chemical reaction that occurs between an acid and a base producing a salt and water</u>. The acids and bases can be strong or weak depending on their degree of ionization in water.

Butyric acid is a weak acid and in water it is ionized in the following way, loosing a proton (H+):

HC4H7O2 (aq) ⇆ H+ (aq) + C4H7O2- (aq)

On the other hand, potassium hydroxide is a strong base, so it will be completely ionized in water:

KOH(aq) → K+(aq) + OH-(aq)

Then the <u>net acid-base reaction</u> between butyric acid and KOH is:

HC4H7O2 (aq) + OH- (aq) ⇆ H2O + C4H7O2- (aq)

It is valid to consider only the OH- produced from the ionization of KOH in water since, as mentioned, this molecule is completely ionized. Also, we do not include the K + in the net equation since it is a spectator ion, it does not undergo chemical changes.

6 0
3 years ago
5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a
max2010maxim [7]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.364g

Mass of H_2O=0.0596g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, \frac{12}{44}\times 0.364=0.0993g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, \frac{2}{18}\times 0.0596=0.0067g of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles]

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = \frac{0.00828}{0.0067}=1.23\approx 1

For Hydrogen = \frac{0.0067}{0.0067}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}

The general formula of an alkane is C_nH_{(2n+2)}, where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

7 0
3 years ago
What is the term that describe two species living together
Sergeu [11.5K]
I think it is <span>Symbiosis. But I dont know how to explain it</span>
3 0
3 years ago
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Which substance is most likely to heat up the fastest?
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The best substance to heat up the fastest would be blue fire
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What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

4 0
3 years ago
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